Found 50 related files. Current in page 1

KUNCI JAWABAN UJIAN TENGAH SEMESTER Kode/Nama Mata Kuliah Waktu/Sifat Ujian : TKC106/Algoritma Pemrograman [Kelas B] : 90 Menit/Open Note [Score = 30] 1. Dua buah bilangan bulat dimasukkan melalui piranti masukan. Buatlah sebuah algoritma (pseudocode) untuk melakukan operasi-operasi berdasarkan kemungkinan-kemungkinan berikut: a. Apabila kedua bilangan adalah bilangan yang berbeda: Bilangan yang lebih kecil dijumlahkan dengan angka 10 dan hasilnya dicetak ke piranti keluaran Bilangan yang lebih besar dijumlahkan dengan angka 5 dan hasilnya dicetak ke piranti keluaran b. Apabila kedua bilangan adalah bilangan yang sama: Kedua bilangan dijumlahkan dan dibagi dengan angka 2, kemudian hasilnya dicetak ke piranti keluaran KETENTUAN: Tidak diperbolehkan menggunakan Operator LOGIKA! Jawaban: Algoritma operasi_PENYELEKSIAN Deklarasi: bil1,bil2: integer Deskripsi: read(bil1,bil2) if bil1 = bil2 then write((bil1 + bil2)/2); else if bil1 < bil2 then write(bil1 + 10) write(bil2 + 5) else write(bil1 + 5) write(bil2 + 10) endif endif [Score = 10] 2. Translasikan algoritma pada soal no (1) ke dalam Bahasa Pascal! Jawaban: program operasi_PENYELEKSIAN; var bil1,bil2: integer; begin bilangan write('Masukkan bilangan pertama! ');readln(bil1); ');readln ln(bil2); write('Masukkan bilangan kedua! ');readln(bil2); if bil1 = bil2 then writeln('Oleh karena kedua bilangan adalah sama, maka hasil penjumlahan kedua bilangan yang kemudian dibagi 2 = ',((bil1 + bil2)/2):3:0) else

Tags:
Kunci jawaban, Education,

... A por whih rel x does this improper integrl onvergec A how tht G(x + I) = xG(x) nd dedue tht G(n + I) = n3 for ny integer n ! HF QIF y g(t ) X R 3 R2 de¢nes smooth urve in the plneF A sf g(H) = H nd kgH (t )k D show tht for ny ! HD kg( )k F woreoverD show tht equlity n our if nd only if one hs g(t ) = vt where v is unit vetor tht does not depend on t F A sf g(H) = HD gH (H) = H nd kgHH (t )k IPD give n upper ound estimte for kg(P)k F hen n this upper ound e hievedc QPF vet r(t ) de¢ne smooth urve tht does not pss through the originF A sf the point a = r(t0 ) is point on the urve tht is losest to the origin @nd not n end point of the urveAD show tht the position vetor r(t0 ) is perpendiulr to the tngent vetor rH (t0 ) F A ht n you sy out point b = r(t1 ) tht is furthest from the originc QQF gonsider two smooth plne urves g1 ; g2 X (H; I) 3 R2 tht do not intersetF uppose 1 nd 2 re points on g1 nd g2 D respetivelyD suh tht the distne j1 2 j is miniE mlF rove tht the stright line 1 2 is norml to oth urvesF R QRF vet h(x; y; z) = H de¢ne smooth surfe in R3 nd let X= (; ; ) e point not on the surfeF sf X (x; y; z) is point on the surfe tht is losest to D show tht the line is perpendiulr to the tngent plne to the surfe t F QSF vet r(t ) desrie smooth urve nd let V e ¢xed vetorF sf rH (t ) is perpendiulr to V for ll t nd if r(H) is perpendiulr to V D show tht r(t ) is perpendiulr to V for ll t F QTF vet f (s) e ny differentile funtion of the rel vrile s F how tht u(x; t ) X= f (x + Qt ) hs the property tht ut = Qux F how tht u lso stis¢es the wve eqution utt = Wuxx F QUF vet u(x; y) e smooth funtionF A sf ux = H with u(H; y) = sin(Qy) D ¢nd u(x; y) F A sf ux = Pxy with u(H; y) = sin(Qy) D ¢nd u(x; y) F A sf ux + uy = H with u(H; y) = sin(Qy) D ¢nd u(x; y) F ss there more thn one suh funtionc dA sf ux + uy = Q Pxy with u(H; y) = sin(Qy) D ¢nd u(x; y) F ss eA sf ux Puy = H with u(H; y) = sin(Qy) D ¢nd u(x; y) F ss there more thn one suh funtionc QVF vet r X= xi + yj nd V(x; y) X= p(x; y)i + q(x; y)j e @smoothA vetor ¢elds nd g R smooth urve in the plneF sn this prolem s is the line integrl s = C V ¡ d r F por eh of the followingD either give proof or give ounterexmpleF A sf g is vertil line segment nd q(x; y) = HD then s = HF A sf g is irle nd q(x; y) = HD then s = HF A sf g is irle entered t the origin nd p(x; y) = q(x; y) D then s = HF dA sf p(x; y) > H nd q(x; y) > HD then s > HF QWF vet g denote the unit irle entered t the origin of the plneD nd h denote the irle of rdius S entered t (P; I) D oth oriented ounterlokwiseF vet denote the ring region etween these R urvesF sf vetor ¢eld V stis¢es div V = HD show tht the line R integrl C V ¡ N ds = D V ¡ N ds = his extends immeditely to the sitution where g nd h re more generl urves nd is the region etween themF por £uid £ow it is n expression of onservtion of mssD sine div V = H mens there re no soures or sinks in the region F...

Tags:
Calculus problems, Education,

Android Evo Laser is a mobile application for controlling Laser device via 3.5mm Audio Jack connected to Smartphone device . The EvoLaser is controlled by PWM(pulse with modulated),meaning the power state of the laser is determined by the duration of active ON period of each cycle. -Power On State of Laser: 18 to 84 % active ON of duty cycle. -Power Off State of Laser: 16% and lower active ON of duty cycle. The workflow of Android Evo Laser app Splash Activity Audio Jack is plugged? yes No Main Activity Error Activity Send the Changes of Tone(mode ,power ,frequency etc). Generate Tone Service The Child Activity of Main Activity Communicate to Laser device with generated Tone Laser Device How does the Android Evo Laser app work? Splash Activity: This is the first activity that runs on launching app. To control Laser device, it is necessary that phone device is connected with laser device via audio bus. So when Audio Jack is plugged in, the control logic goes to Main Activity, otherwise goes to Error Activity. Code: public void gotoMainPage() { if(audioManager.isWiredHeadsetOn()) { Intent intent = new Intent(this, MainActivity.class); intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP); startActivity(intent); finish(); } else{ Intent intent = new Intent(this, ErrorActivity.class); intent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP); startActivity(intent); finish(); } } Main Activity: If audio jack is plugged in, the control logic goes to Main Activity when app launches. In this activity start GenerateToneService for communicating to Laser device. Code: Intent intent=new Intent(MainActivity.this,GenerateToneService.class); startService(intent); And start child activities (Continuous Activity, Momentary Activity, Strobe Activity etc). The Protocol for Generating Tone (ToneManager): To control laser device, it is needed to make a tone signal. In this protocol we refer the formulas as follows: -Power On State of Laser: 18 to 84 % active ON of duty cycle. -Power Off State of Laser: 16% and lower active ON of duty cycle. -The Member Variable of ToneManager class. mode:The Integer variable which indicates the tone mode. This can be one of 4 modes (Continuous,Momentary,Strobe,Fade). power:The Double variable which controls the strength of the laser. The means of this variable ...

Tags:
Android evo, Gadgets,

RAPORLAMA ÖRNEĞİ-1 TALEP: Erciyes Üniversitesi Fen Fakültesi Matematik Bölümünde eğitim gören Mustafa MOLU isimli öğrenci LYS sınavı ile Fakültemiz Elektrik-Elektronik Mühendisliği Bölümünü kazanmış olup, önceki bölümünde almış olduğu bazı derslerden muafiyet talep etmektedir. GEREĞİ: Bu öğrencinin muaf tutulduğu toplam dersi saati 13 olup, sınıf muafiyeti için gerekli olan %70 lik muafiyet koşulunu sağlamadığından dolayı bu öğrenciye “Ders Muafiyeti Raporu” düzenlenir. Talepte bulunan öğrenci Erciyes Üniversitesi öğrencisi olduğu için önceki bölümündeki almış olduğu ve muaf olduğu derslerin notları Fakültemizin sistemine aynen aktarılacaktır. Düzenlenecek raporda notlar belirtildikten sonra karşısına “BAŞARILI” yazılacaktır. Şartlı geçilmiş bir ders ise (DC ve DD) “ŞARTLI GEÇER” olarak yazılacak ve not ortalamasına etki ettirilecektir. Bu öğrenci ve bu tip ders muafiyetleri için örnek rapor aşağıda verilmiştir. NOT: Bölümlerin intibak komisyonu Başkanı, hazırlayacakları rapor için Bölüm Başkanlıklarına aşağıdaki gibi bir üst yazı sunacaktır. Bölümümüz…………………..numaralı öğrencilerinden …………………………………….’ın not durum belgesi ve ders müfredatı komisyonumuzca incelenmiş ve Ders Muafiyet Raporu ekte sunulmuştur. Bilgilerinize arz ederim. TALEP: Süleyman Demirel Üniversitesi Mühendislik Fakültesinde eğitim gören Ömer Fatih ÇITIRIK isimli öğrenci LYS sınavı ile Fakültemiz Tekstil Mühendisliği Bölümünü kazanmış olup, önceki bölümünde almış olduğu bazı derslerden muafiyet talep etmektedir. GEREĞİ: Bu öğrencinin muaf tutulduğu toplam dersi saati 50 olup, 2.sınıf 3. yarıyıla intibakı için gerekli olan ilk iki yarıyılın toplam ders saatlerinin en az %70 inden muaf olma koşulunu sağladığından dolayı bu öğrenciye “Sınıf İntibakı Raporu” düzenlenir. Talepte bulunan öğrenci Üniversitemiz dışından bir öğrenci olduğu için önceki bölümündeki almış olduğu ve muaf olduğu derslerin notları Fakültemizin sistemine etki ettirilmeyecektir. Düzenlenecek raporda notlar belirtildikten sonra karşısına “MUAF” ya da “ALACAK” yazılacaktır. Bu öğrenci ve bu tip sınıf intibakları için örnek rapor aşağıda verilmiştir...

Tags:
örnek rapor, Journal,

Dosen Pengampu: Noor Ifada KUNCI JAWABAN UJIAN TENGAH SEMESTER Kode/Nama Mata Kuliah Waktu/Sifat Ujian : TKC106/Algoritma Pemrograman [Kelas B] : 90 Menit/Open Note [Score = 30] 1. Dua buah bilangan bulat dimasukkan melalui piranti masukan. Buatlah sebuah algoritma (pseudocode) untuk melakukan operasi-operasi berdasarkan kemungkinan-kemungkinan berikut: a. Apabila kedua bilangan adalah bilangan yang berbeda: Bilangan yang lebih kecil dijumlahkan dengan angka 10 dan hasilnya dicetak ke piranti keluaran Bilangan yang lebih besar dijumlahkan dengan angka 5 dan hasilnya dicetak ke piranti keluaran b. Apabila kedua bilangan adalah bilangan yang sama: Kedua bilangan dijumlahkan dan dibagi dengan angka 2, kemudian hasilnya dicetak ke piranti keluaran KETENTUAN: Tidak diperbolehkan menggunakan Operator LOGIKA! Jawaban: Algoritma operasi_PENYELEKSIAN Deklarasi: bil1,bil2: integer Deskripsi: read(bil1,bil2) if bil1 = bil2 then write((bil1 + bil2)/2); else if bil1 < bil2 then write(bil1 + 10) write(bil2 + 5) else write(bil1 + 5) write(bil2 + 10) endif endif [Score = 10] 2. Translasikan algoritma pada soal no (1) ke dalam Bahasa Pascal! Jawaban: program operasi_PENYELEKSIAN; var bil1,bil2: integer; begin bilangan write('Masukkan bilangan pertama! ');readln(bil1); ');readln ln(bil2);...

Tags:
Kunci jawaban, Education,

Licensed to: iChapters User 7th edition College Algebra and Trigonometry College Algebra and Trigonometry Richard N. Aufmann Vernon C. Barker Richard D. Nation 7th edition Cengage Learning developed and published this special edition for the beneﬁt of students and faculty outside the United States and Canada. Content may signiﬁcantly differ from the North American college edition. If you purchased this book within the United States or Canada, you should be aware that it has been imported without the approval of the publisher or the author. Aufmann Barker Nation Thank you for choosing a Cengage Learning International Edition. Cengage Learning’s mission is to shape the future of global learning by delivering consistently better learning solutions for students, instructors, and institutions worldwide. This textbook is the result of an innovative and collaborative global development process designed to engage students and deliver content and cases with global relevance. NOT AUTHORIZED FOR SALE IN THE U.S.A. OR CANADA For product information: www.cengage.com/international Visit your local oﬃce: www.cengage.com/global Visit our corporate website: www.cengage.com 1439049394_ise_cvr.indd 1 ISE/Aufmann/Barker/Nation, College Algebra and Trigonometry, 7th Edition ISBN-1-4390-4939-4 ©2011 Designer: Denise Davidson Text printer: Quebecor World/Taunton Cover printer: Quebecor World/Taunton Binding: Case Trim: 8.5" x 10" CMYK 1/9/10 5:07 PM 49394_00_FM.qxd 1/9/10 Licensed to: iChapters User 12:09 PM Page iv College Algebra and Trigonometry, Seventh Edition Richard N. Aufmann, Vernon C. Barker, Richard D. Nation Acquisitions Editor: Gary Whalen Developmental Editor: Carolyn Crockett Assistant Editor: Stefanie Beeck © 2011, 2008 Brooks/Cole, Cengage Learning ALL RIGHTS RESERVED. No part of this work covered by the copyright herein may be reproduced, transmitted, stored, or used in any form or by any means graphic, electronic, or mechanical, including but not limited to photocopying, recording, scanning, digitizing, taping, Web distribution, information networks, or information storage and retrieval systems, except as permitted under Section 107 or 108 of the 1976 United States Copyright Act, without the prior written permission of the publisher. Editorial Assistant: Guanglei Zhang Media Editor: Lynh Pham Marketing Manager: Myriah Fitzgibbon Marketing Assistant: Angela Kim Marketing Communications Manager: Katy Malatesta For product information and technology assistance, contact us at Cengage Learning Customer & Sales Support, 1-800-354-9706. For permission to use material from this text or product, submit all requests online at www.cengage.com/permissions. Further permissions questions can be e-mailed to permissionrequest@cengage.com. Content Project Manager: Jennifer Risden Creative Director: Rob Hugel Library of Congress Control Number: 2009938510 Art Director: Vernon Boes International Student Edition: Print Buyer: Karen Hunt ISBN-13: 978-1-4390-4939-6 Rights Acquisitions Account Manager, Text: Roberta Broyer ISBN-10: 1-4390-4939-4 Rights Acquisitions Account Manager, Image: Don Schlotman Production Service: Graphic World Inc. Text Designer: Diane Beasley Brooks/Cole 20 Davis Drive Belmont, CA 94002-3098 USA Photo Researcher: Prepress PMG Copy Editor: Graphic World Inc. Illustrator: Network Graphics; Macmillan Publishing Solutions Cengage Learning is a leading provider of customized learning solutions with office locations around the globe, including Singapore, the United Kingdom, Australia, Mexico, Brazil, and Japan. Locate your local office at www.cengage.com/global. Cover Designer: Lisa Henry Cover Image: Chad Ehlers, Getty Images Compositor: Macmillan Publishing Solutions Cengage Learning products are represented in Canada by Nelson Education, Ltd. To learn more about Brooks/Cole, visit www.cengage.com/brookscole Purchase any of our products at your local college store or at our preferred online store www.CengageBrain.com. Printed in Canada 1 2 3 4 5 6 7 14 13 12 11 10 Copyright 2011 Cengage Learning, Inc. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. 48610_01_ch0p_s01_001-016.qxd Licensed to: iChapters User CHAPTER 10/14/09 5:16 PM P Page 1 PRELIMINARY CONCEPTS AFP/Getty Images P.1 The Real Number System P.2 Integer and Rational Number Exponents P.3 Polynomials P.4 Factoring P.5 Rational Expressions P.6 Complex Numbers Albert Einstein proposed relativity theory more than 100 years ago, in 1905. Martial Trezzini/epa/CORBIS Relativity Is More Than 100 Years Old The Large Hadron Collider (LHC). Atomic particles are accelerated to high speeds inside the long structure in the photo above. By studying particles moving at speeds that approach the speed of light, physicists can confirm some of the tenets of relativity theory. Positron emission tomography (PET) scans, the temperature of Earth’s crust, smoke detectors, neon signs, carbon dating, and the warmth we receive from the sun may seem to be disparate concepts. However, they have a common theme: Albert Einstein’s Theory of Special Relativity. When Einstein was asked about his innate curiosity, he replied: The important thing is not to stop questioning. Curiosity has its own reason for existing. One cannot help but be in awe when he contemplates the mysteries of eternity, of life, of the marvelous structure of reality. It is enough if one tries merely to comprehend a little of this mystery every day. Today, relativity theory is used in conjunction with other concepts of physics to study ideas ranging from the structure of an atom to the structure of the universe. Some of Einstein’s equations require working with radical expressions, such as the expression given in Exercise 139 on page 31; other equations use rational expressions, such as the expression given in Exercise 64 on page 59. 1 Copyright 2011 Cengage Learning, Inc. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. 48610_01_ch0p_s01_001-016.qxd Licensed to: iChapters User 2 CHAPTER P 10/14/09 5:16 PM Page 2 PRELIMINARY CONCEPTS SECTION P.1 Sets Union and Intersection of Sets Interval Notation Absolute Value and Distance Exponential Expressions Order of Operations Agreement Simplifying Variable Expressions The Real Number System Sets Human beings share the desire to organize and classify. Ancient astronomers classified stars into groups called constellations. Modern astronomers continue to classify stars by such characteristics as color, mass, size, temperature, and distance from Earth. In mathematics it is useful to place numbers with similar characteristics into sets. The following sets of numbers are used extensively in the study of algebra. 51, 2, 3, 4, Á 6 Natural numbers 5 Á , -3, -2, -1, 0, 1, 2, 3, Á 6 Integers 5all terminating or repeating decimals6 Rational numbers 5all nonterminating, nonrepeating decimals6 Irrational numbers 5all rational or irrational numbers6 Real numbers If a number in decimal form terminates or repeats a block of digits, then the number is a rational number. Here are two examples of rational numbers. 0.75 is a terminating decimal. 0.245 is a repeating decimal. The bar over the 45 means that the digits 45 repeat without end. That is, 0.245 = 0.24545454 Á . p , where p and q are inteq gers and q Z 0. Examples of rational numbers written in this form are Rational numbers also can be written in the form 3 4 Note that Math Matters Archimedes (c. 287–212 B.C.) was the first to calculate p with any degree of precision. He was able to show that 3 10 1 6 p 6 3 71 7 from which we get the approximation 3 1 22 = L p 7 7 The use of the symbol p for this quantity was introduced by Leonhard Euler (1707–1783) in 1739, approximately 2000 years after Archimedes. 27 110 - 5 2 7 1 -4 3 7 n = 7, and, in general, = n for any integer n. Therefore, all integers are rational 1 1 numbers. p , the decimal form of the rational q number can be found by dividing the numerator by the denominator. When a rational number is written in the form 3 = 0.75 4 27 = 0.245 110 In its decimal form, an irrational number neither terminates nor repeats. For example, 0.272272227 Á is a nonterminating, nonrepeating decimal and thus is an irrational number. One of the best-known irrational numbers is pi, denoted by the Greek symbol p . The number p is defined as the ratio of the circumference of a circle to its diameter. Often in applications the rational number 3.14 or the rational 22 number is used as an approximation of the irrational number p. 7 Every real number is either a rational number or an irrational number. If a real number is written in decimal form, it is a terminating decimal, a repeating decimal, or a nonterminating and nonrepeating decimal. Copyright 2011 Cengage Learning, Inc. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. 48610_01_ch0p_s01_001-016.qxd Licensed to: iChapters User 10/14/09 5:16 PM Page 3 P.1 The relationships among the various sets of numbers are shown in Figure P.1. Math Matters Sophie Germain (1776–1831) was born in Paris, France. Because enrollment in the university she wanted to attend was available only to men, Germain attended under the name of Antoine-August Le Blanc. Eventually her ruse was discovered, but not before she came to the attention of Pierre Lagrange, one of the best mathematicians of the time. He encouraged her work and became a mentor to her. A certain type of prime number is named after her, called a Germain prime number. It is a number p such that p and 2p + 1 are both prime. For instance, 11 is a Germain prime because 2(11) + 1 = 23 and 11 and 23 are both prime numbers. Germain primes are used in public key cryptography, a method used to send secure communications over the Internet. Alternative to Example 1 For each number, check all that apply. N = Natural I = Integer Q = Rational R = Real N Ϫ57 3.3719 7.42917 0 1.191191119 . . . 101 3 THE REAL NUMBER SYSTEM I Q R Positive integers (natural numbers) 7 1 103 Integers Zero 0 −201 7 0 Rational numbers 3 4 −5 Real numbers 3 4 3.1212 −1.34 −5 3.1212 −1.34 7 Irrational numbers Negative integers −201 −8 1 −5 −0.101101110... √7 π −0.101101110... √7 π −5 0 103 −201 Figure P.1 Prime numbers and composite numbers play an important role in almost every branch of mathematics. A prime number is a positive integer greater than 1 that has no positiveinteger factors1 other than itself and 1. The 10 smallest prime numbers are 2, 3, 5, 7, 11, 13, 17, 19, 23, and 29. Each of these numbers has only itself and 1 as factors. A composite number is a positive integer greater than 1 that is not a prime number. For example, 10 is a composite number because 10 has both 2 and 5 as factors. The 10 smallest composite numbers are 4, 6, 8, 9, 10, 12, 14, 15, 16, and 18. EXAMPLE 1 Classify Real Numbers Determine which of the following numbers are a. integers b. rational numbers c. irrational numbers d. real numbers e. prime numbers f. composite numbers -0.2, 0, 0.3, 0.71771777177771 Á , p, 6, 7, 41, 51 Solution a. Integers: 0, 6, 7, 41, 51 b. Rational numbers: -0.2, 0, 0.3, 6, 7, 41, 51 c. Irrational numbers: 0.71771777177771..., p d. Real numbers: -0.2, 0, 0.3, 0.71771777177771 Á , p, 6, 7, 41, 51 e. Prime numbers: 7, 41 f. Composite numbers: 6, 51 Try Exercise 2, page 14 Each member of a set is called an element of the set. For instance, if C = 52, 3, 56, then the elements of C are 2, 3, and 5. The notation 2 ʦ C is read “2 is an element of C.” 1 A factor of a number divides the number evenly. For instance, 3 and 7 are factors of 21; 5 is not a factor of 21. Copyright 2011 Cengage Learning, Inc. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part...

Tags:
Algebra trigonometry, Education,