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### Triple your Strength by using Digital Maps Slide World

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Presentation Play an indispensable role in the success of any conference and meeting. Many of the small to big organizations are using PowerPoint map templates for making their presentation interactive.

### Astute Recognized by Storage Strategies NOW as a Game Changing Networked Flash Solution for Both NFS and iSCSI Physical and Virtual Environments

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Analyst Report Outlines the Advantages of Astute's ViSX Solid State Flash Appliance with New Features for NFS and OpenStack Support for the Cloud

### Maintain Your Entertainment Quotient Higher With Ben10 Video & Flash Games

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We have the most effective Ben 10 Video games from the Cartoon Network and throughout the web. New Ben10 Games are added each day for our loyal local community to perform and enjoy at no cost. Much more facts accessible on our site

### SNMPTN 2012 Matematika - zenius.net

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### Soal-Soal dan Pembahasan Matematika IPA SNMPTN 2012 ...

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Soal-Soal dan Pembahasan Matematika IPA SNMPTN 2012 Tanggal Ujian: 13 Juni 2012 1. Lingkaran (x + 6)2 + (y + 1)2 = 25 menyinggung garis y = 4 di titik... A. ( -6, 4 ) B. ( 6 , 4) C. ( -1, 4 ) D. ( 1, 4 ) E. ( 5 , 4 ) Jawab: BAB XI Lingkaran Masukkan nilai y=4 pada persamaan (x + 6)2 + (4 + 1)2 = 25 (x + 6)2 = 25 – 25 = 0 x = -6 Didapat titik x = -6 dan y = 4  (-6,4) Jawabannya A 2. Jika 2x3 – 5x2 – kx + 18 dibagi x - 1 mempunyai sisa 5, maka nilai k adalah... A. -15 B. -10 C. 0 D. 5 E. 10 Jawab: BAB XII Suku Banyak Metoda Horner x3 x= 1 2 x2 x -k 18 2 2 -5 -3 -3 - k -3 ( -3- k) + = kalikan dengan x =1 (15 – k)  sisa =5 15 – k = 5 k = 15 – 5 = 10 Jawabannya E www.belajar-matematika.com 1 3. Luas daerah yang dibatasi oleh kurva y = x2, y = 1, dan x = 2 adalah... A. ∫ (1 − B. ∫ ( ) C. ∫ ( − 1) − 1) D. ∫ (1 − Jawab BAB XVI Integral E. ∫ ( ) − 1) Buat sketsa gambar untuk mengetahui batas luas: terlihat bahwa bidang luasnya (arsiran) bagian atasnya adalah y = x 2 dan bagian bawahnya y = 1 dengan dibatasi oleh batas atas x = 2 dan batas bawah x =1. Dalam notasi integralnya : b ∫ ( b b a a a L =  y2 dx -  y1 dx =  ( y 2  y1) dx − 1) Jawabannya C 4. ( ( A. B. ) ) = .... C. E. D. www.belajar-matematika.com 2 Jawab: BAB VII Trigonometri ( ( + 2 sin cos ) ) = = = =1 = 2 Jawabannya E 5. Lingkaran (x - 3)2 + (y - 4)2 = 25 memotong sumbu –x di titik A dan B. Jika P adalah titik pusat lingkaran tersebut, maka cos ∠APB = ... A. C. B. E. D. Jawab: BAB XI Lingkaran dan BAB VII Trigonometri Sketsa gambar: Lingkaran dengan pusat (3,4) APB merupakan segitiga. www.belajar-matematika.com 3 Untuk menjawab soal ini digunakan teorema di bawah ini: Aturan sinus dan cosinus C  b  a  A c B Aturan cosinus 1. a 2 = b 2 + c 2 - 2bc cos  2. b 2 = a 2 + c 2 - 2ac cos  3. c 2 = a 2 + b 2 - 2ab cos  Kita pakai rumus (3) c = AB = 6 a = b = AP = PB = √3 + 4 = √25 = 5 c 2 = a 2 + b 2 - 2ab cos P 2ab cos P = + − cos P = = = = . . . Jawabannya A 6. Grafik fungsi f(x) = ax3 – bx2 + cx + 12 naik jika.... A. b2 – 4ac < 0 dan a > 0 B. b2 – 4ac < 0 dan a < 0 C. b2 – 3ac > 0 dan a < 0 D. b2 – 3ac < 0 dan a > 0 E. b2 – 3ac < 0 dan a < 0 Jawab: BAB XV Differensial www.belajar-matematika.com 4 Syarat fungsi naik ( )>0 3ax2 - 2bx + c > 0  fungsi naik ( - , 0, + ) * variabel x2 > 0 3a > 0 a>0 *D<0 ( ) > 0 , maka tidak ada titik potong dan singgung di sb x sehingga D < 0  karena (-2b)2 – 4.3a.c < 0 4b2 – 12.a.c < 0 b2 – 3 ac < 0 didapat a > 0 dan b2 – 3 ac < 0 Jawabannya D 7. →0 = .... E. √3 √ A. -1 C. 1 B. -0 D. Jawab: XIV Limit Fungsi →0 = →0 = = = →0 →0 1 . 1. = = =1 Jawabannya C www.belajar-matematika.com

### Soal dan Pembahasan Matematika IPA SNMPTN 2011

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### Simulasi Soal Snmptn 2011

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Gunakan PETUNJUK A untuk menjawab soal nomor 31 sampai dengan nomor 45! Text 1 The first ancient DNA sequences to be gathered ‐ 3400 base pairs from a 2400‐year‐old Egyptian mummy − were a proof of principle. A full genome sequence would be far more informative − perhaps explaining what killed King Tut, for instance. At present, Inuk's is the only published ancient human genome. However, a team led by Svante Paabo and Ed Green at the Max Planck Institute for Evolutionary Anthropology in 5 Leipzig, Germany, will soon publish the complete genome sequence combined together from several Neanderthals, from between 38,000 and 70,000 years ago. Neanderthals are not the only hominids whose genomes could be sequenced, says Willerslev. Homo erectus, a species that emerged in Africa about 2 million years ago, survived in east Asia until less than 100,000 years ago. If well‐preserved bones can be found, a genome might be possible, Willerslev says. 10 Willerslev's laboratory has just received bones from Spain belonging to Homo heidelbergensis, the predecessor to Neanderthals. "We are basically starting on it right now," he says. If these genomes ever materialize ‐ and that's a big if ‐ they could lead to a better understanding of how different hominid species are related, and when and where they branched off. If the genetic information is good enough, it may tell us something about the nature of past peoples − possibly even what they looked like. Ancient human genomes 15 could give us insights into the evolution of our own species, explaining when genes involved in disease and higher cognitive skills emerged. But DNA is not forever. As it ages, its long strands shred into ever smaller pieces. Eventually they become too small to reassemble, and all information is lost. "There seems to be a time horizon of 100,000 years or so under most preservation conditions during which intact DNA survives," Green says. Stephan 20 Schuster at Pennsylvania State University, who led the woolly mammoth genome project, thinks ancient genomics is already plateauing. Large chunks of Inuk's genome couldn't be filled in because his DNA had crumbled into small pieces. "We will face an uphill battle in trying to apply this to a large number of human remains," he says. 31. With reference to the whole text, the writer mainly deals with the topic on … (A) the use of ancient DNA in anthropology. (B) the past life of the Neanderthals. (C) the role of DNA in fossil studies. (D) DNA research on the Neanderthals. (E) DNA engineering in the Max Planck Institute. 32. The writer is mainly of the opinion that tracing ancient humans’ life using their DNA … (A) is technologically possible through it has natural challenges. (B) promises a new horizon of understanding past illnesses. (C) is a new breakthrough in modern anthropological studies. (D) provides a better picture of old peoples’ DNA structures. ...

### Presentasi SBMPTN Info Day 2013.pdf

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SBMPTN Info Day 2013 Acara Sosialisasi Seleksi Bersama Masuk Perguruan Tinggi Negeri Tahun 2013 Dr. Emil Budianto Ketua Pantia Lokal SBMPTN Jakarta SELEKSI MAHASISWA MASUK PTN PRESTASI AKADEMIK SNMPTN KEBIJAKAN PENERIMAAN MAHASISWA PTN UJIAN TERTULIS SBMPTN Pola seleksi yang dilaksanakan secara bersama oleh PTN di seluruh Indonesia yang diselenggarakan melalui ujian tulis KARAKTERISTIK TES TERTULIS 1 2 • mengukur kemampuan penalaran atau kemampuan berpikir tingkat tinggi (higher order thinking) yang memprediksi keberhasilan calon mahasiswa di semua program studi di Perguruan Tinggi. • terdiri dari Tes Potensi Akademik (TPA), Tes Kemampuan Dasar Umum (TKDU), Tes Kemampuan Dasar Sains dan Teknologi (TKD Saintek), dan Tes Kemampuan Dasar Sosial dan Humaniora (TKD Soshum). Perbedaan SNMPTN 2012 dengan SBMPTN 2013

### ANALISIS SOAL SNMPTN BIOLOGI ... - repository@UPI

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