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Getting started with Logitech® Wireless Speaker Adapter for ...

Setting up the wireless speaker adapter 1. Connect the power supply to the wireless speaker adapter. 2. Plug the power supply into an AC outlet. 3. Connect the wireless speaker adapter to powered speakers or an AV receiver using the included Y-cable. 4. Press the connect button on the wireless speaker adapter to place it in Bluetooth® pairing mode. 5. The wireless speaker adapter connects to smart phones, tablets, and Bluetooth-enabled computers. Put your Bluetooth device in pairing mode. (Refer to the documentation that comes with your device for pairing instructions.) If your Bluetooth device requests a security code, PIN, or pass code, enter 0000. The Bluetooth connection is made. You’re ready to play some music. For PC users: Specifying the wireless speaker adapter as the default audio output device for your operating system Windows® XP 1. Go to the Start/Control Panel/Sounds and Audio Devices/Audio tab. 2. In the Sound Playback/Default Device window, choose Logitech Wireless Speaker Adapter. 3. Click OK, and then restart your media application. Windows® Vista and Windows® 7 1. Go to the Start/Control Panel/Hardware and Sound/Sound/Playback Devices tab. 2. Choose Playback Devices, and then choose Logitech Wireless Speaker Adapter. 3. Click Set Default, and then click OK. 4. Restart your media application. Mac® OS X 1. Open System Preferences. 2. Select the Sound/Output tab. 3. Select Logitech Wireless Speaker Adapter. 4. Restart your media application. Wireless connection indications Einrichten des Wireless Speaker Adapter 1. Schließen Sie das Stromkabel an den Adapter an. 2. Schließen Sie das Stromkabel an eine Steckdose an. 3. Schließen Sie den Wireless Speaker Adapter mithilfe des mitgelieferten Y-Kabels an Lautsprecher mit eigenem Stromanschluss oder an einen AVEmpfänger an. 4. Drücken Sie die Verbindungstaste auf dem Adapter, um ihn in den Bluetooth®-Pairing-Modus zu versetzen. 5. Der Wireless Speaker Adapter kann eine Verbindung zu Smartphones, Tablet-PCs und Bluetooth-fähigen Computern herstellen. Versetzen Sie Ihr Bluetooth-Gerät in den Pairing-Modus. (In der Dokumentation zu Ihrem Gerät finden Sie Anweisungen zum Pairing.) Falls Ihr Bluetooth-Gerät Sie zur Eingabe eines Sicherheitscodes, einer PIN oder eines Passcodes auffordert, geben Sie 0000 ein. Die Bluetooth-Verbindung wurde hergestellt. Sie können jetzt Musik hören. Für PC-Benutzer: Einrichten des Wireless Speaker Adapter als Standardgerät für die Audioausgabe auf Ihrem Betriebssystem Windows® XP 1. Klicken Sie auf „Start > Systemsteuerung > Sounds und Audiogeräte“ und wählen Sie die Registerkarte „Audio“. 2. Wählen Sie im Abschnitt „Soundwiedergabe“ unter „Standardgerät“ den Logitech Wireless Speaker Adapter. 3. Klicken Sie auf „OK“ und starten Sie Ihre Multimedia-Anwendung neu. Windows® Vista und Windows® 7 1. Klicken Sie auf „Start > Systemsteuerung > Hardware und Sound > Sound“ und wählen Sie die Registerkarte „Wiedergabegeräte“. 2. Wählen Sie „Wiedergabegeräte“ und anschließend Logitech Wireless Speaker Adapter. 3. Klicken Sie auf „Als Standard“ und anschließend auf „OK“. 4. Starten Sie die Multimedia-Anwendung neu. Mac® OS X 1. Öffnen Sie die Systemeinstellungen. 2. Wählen Sie die Registerkarte „Ton/Ausgabe“. 3. Wählen Sie den Logitech Wireless Speaker Adapter. 4. Starten Sie die Multimedia-Anwendung neu.

Acer Aspire 5315-2713 Notebook PC - static.highspeedb...

Aspire 5315-2713 Quick Spec Part Number: LX.ALC0Y.336 UPC: 099802477325 Operating system1 Windows Vista™ Home Basic Platform1 Intel® Celeron® Dual Core mobile processor T1400 (512 KB L2 cache, 1.73 GHz, 533 MHz FSB) Mobile Intel® GL960 Express Chipset Acer InviLink™ 802.11b/g Wi-Fi CERTIFIED® solution, supporting Acer SignalUp™ wireless technology System memory1, 2 1 GB of DDR2 533 MHz memory, upgradeable to 2 GB using two soDIMM modules (dual-channel support) Display 15.4" WXGA high-brightness (200-nit) Acer CrystalBrite™ TFT LCD, 1280 x 800 pixel resolution, supporting simultaneous multi-window viewing via Acer GridVista™ Graphics1 Mobile Intel® GL960 Express chipset with integrated 3D graphics, featuring Intel® Graphics Media Accelerator (GMA) X3100 with up to 358 MB of Intel® Dynamic Video Memory Technology 4.0 (8 MB of dedicated system memory, up to 350 MB of shared system memory), supporting Microsoft® DirectX® 9 and DirectX® 103 Dual independent display support 16.7 million colors External resolution/refresh rate: • 2048 x 1536: 75/60 Hz • 1920 x 1440: 85/75/60 Hz • 1920 x 1200: 75/60 Hz • 1920 x 1080: 100/85/75/60 Hz • 1600 x 1200: 120/100/85/75/60 Hz • 1600 x 900: 120/100/85/75/60 Hz • 1400 x 1050: 85/75/60 Hz • 1280 x 1024: 120/100/85/75/60 Hz • 1280 x 960: 85/75/60 Hz • 1280 x 768: 85/75/60 Hz • 1280 x 720: 100/85/75/60 Hz • 1024 x 768: 120/100/85/75/60 Hz • 800 x 600: 120/100/85/72/60 Hz MPEG-2/DVD hardware-assisted capability (acceleration) S-video/TV-out (NTSC/PAL) support Aspire 5315 Quick Spec 1 Aspire 5315-2713 Quick Spec Part Number: LX.ALC0Y.336 UPC: 099802477325 Acer Arcade™ featuring Acer CinemaVision™ and Acer ClearVision™ technologies Audio Intel® High Definition Audio support with two built-in stereo speakers (2 W) MS-Sound compatible Storage1 120 GB or larger hard disk drive4 Optical media drive 8X DVD-Super Multi double-layer drive: • • Communication Read: 24X CD-ROM, 24X CD-R, 24X CD-RW, 8X DVD-ROM, 8X DVD-R, 8X DVD+R, 6X DVD-ROM DL (double-layer), 6X DVD-R DL (double-layer), 6X DVD+R DL (double-layer), 6X DVD-RW, 6X DVD+RW, 5X DVD-RAM Write: 24X CD-R, 16X CD-RW, 8X DVD-R, 8X DVD+R, 4X DVD-R DL (double-layer), 4X DVD+R DL (double-layer), 6X DVD-RW, 8X DVD+RW, 5X DVD-RAM WLAN: Acer InviLink™ 802.11b/g Wi-Fi CERTIFIED® network connection, supporting Acer SignalUp™ wireless technology LAN: 10/100MHz Ethernet, Wake-on-LAN ready Modem: 56K ITU V.92 with PTT approval5, Wake-on-Ring ready Dimensions and weight1 366 (W) x 274 (D) x 33.6/42.6 (H) mm (14.4 x 10.8 x 1.3/1.7 inches) 2.80 kg (6.17 lbs.) with 6-cell battery Power1 ACPI 3.0 CPU power management standard: supports Standby and Hibernation power-saving modes 44.4 W 4000 mAh Li-ion 6-cell battery pack: • 2.0-hour battery life6 • 2.5-hour rapid charge system-off • 3.5-hour charge-in-use 3-pin 65 W AC adapter Special keys and controls1 88-/89-key keyboard with inverted "T" cursor layout, 2.5 mm (minimum) key travel (Japan 93 keys) Seamless touchpad with 4-way scroll button 12 function keys, four cursor keys, two Windows® keys, hotkey controls, embedded numeric keypad, international language support, independent US and Euro dollar sign keys, media control keys Empowering Key Aspire 5315 Quick Spec ...

Acer: Aspire 5920G Series Service Guide - tim.id.au

Aspire 5920G Series Service Guide Service guide files and updates are available on the ACER/CSD web; for more information, please refer to http://csd.acer.com.tw PRINTED IN TAIWAN Revision History Please refer to the table below for the updates made on Aspire Chapla service guide. Date II Chapter Updates Copyright Copyright © 2007 by Acer Incorporated. All rights reserved. No part of this publication may be reproduced, transmitted, transcribed, stored in a retrieval system, or translated into any language or computer language, in any form or by any means, electronic, mechanical, magnetic, optical, chemical, manual or otherwise, without the prior written permission of Acer Incorporated. Disclaimer The information in this guide is subject to change without notice. Acer Incorporated makes no representations or warranties, either expressed or implied, with respect to the contents hereof and specifically disclaims any warranties of merchantability or fitness for any particular purpose. Any Acer Incorporated software described in this manual is sold or licensed "as is". Should the programs prove defective following their purchase, the buyer (and not Acer Incorporated, its distributor, or its dealer) assumes the entire cost of all necessary servicing, repair, and any incidental or consequential damages resulting from any defect in the software. Acer is a registered trademark of Acer Corporation. Intel is a registered trademark of Intel Corporation. Pentium and Pentium II/III are trademarks of Intel Corporation. Other brand and product names are trademarks and/or registered trademarks of their respective holders. III Conventions The following conventions are used in this manual: SCREEN MESSAGES NOTE Gives bits and pieces of additional information related to the current topic. WARNING Alerts you to any damage that might result from doing or not doing specific actions. CAUTION Gives precautionary measures to avoid possible hardware or software problems. IMPORTANT IV Denotes actual messages that appear on screen. Reminds you to do specific actions relevant to the accomplishment of procedures. Preface Before using this information and the product it supports, please read the following general information. 1. This Service Guide provides you with all technical information relating to the BASIC CONFIGURATION decided for Acer's "global" product offering. To better fit local market requirements and enhance product competitiveness, your regional office MAY have decided to extend the functionality of a machine (e.g. add-on card, modem, or extra memory capability). These LOCALIZED FEATURES will NOT be covered in this generic service guide. In such cases, please contact your regional offices or the responsible personnel/channel to provide you with further technical details.

EMERGENCY POWER KIT FOR CHEVROLET VOLT

EMERGENCY POWER KIT FOR CHEVROLET VOLT FEATURES:  Utilizes 12V accessory power system of the Volt  Provides backup power without needing to run the Volt’s gasoline engine*  Includes all hardware and accessories designed specifically for the Volt  No drilling or other modifications to the Volt are needed  Quick disconnect system allows for easy connection of inverter  Maximum Inverter Size supported: 1000W with 2000W surge.  Installation Time: 30 minutes DESCRIPTION: The EVEX-1000W is a do-it-yourself** wiring kit to provide emergency backup power from your Chevrolet Volt. The kit is custom-designed for the Volt, to allow for a hidden installation with power connector access through the fuse box compartment on the left-side of the hatch storage area. The kit includes a fuse holder with fuse, heavy duty wires cut to length with soldered leads and pre-installed wire terminals, as well as a heavy duty connector set to allow quick connections to the inverter of your choice as needed. The kit is designed for a maximum inverter size of 1000W with 2000W surge. This maximum size is designed to work within the limits of the Volt’s 12V power electronics design. WHAT’S INCLUDED:  Fuse holder and fuse, with heavy duty Velcro to secure holder  4AWG wiring for positive and negative 12V connections  8AWG wiring for chassis connection (required by some inverters)  High current DC connector for quick inverter connect when emergency power is needed  Step by step instruction manual for installation  1000W true sine wave inverter (optional, select when ordering) More details including frequently asked questions are available on our website. * The vehicle is required to be turned on for emergency back-up power. In most scenarios, the engine will not run, and the 12V system will get its power from the Volt’s high voltage traction battery. In some scenarios however, the engine may cycle on and off intermittently. This may occur if the high voltage traction battery is depleted, if the vehicle is in mountain or hold mode, if temperatures are below 40F, or if the vehicle’s hood is open. Always make sure vehicle is in a properly ventilated area! Exhaust will be emitted when engine is running. ** If you are not experienced and comfortable with 12V wiring, please seek the assistance of a professional. EVEX-1000W sales@evextend.com  http://www.evextend.com

The Curtain Rod Shop - Stylish Curtain Rod Hardware Gives New Look to Home

The Curtain Rod Shop provides high-quality contemporary and modern curtain rods in all types of widths, finishes, and materials for over 10 years. With expert guidance and a specialization in curtain rod hardware. For more details visit http://thecurtainrodshop.com/blog/enhance-your-home-decor-with-contemporary-stylish-curtain-rod-hardware/

SNMPTN 2012 Matematika - zenius.net

SNMPTN 2012 Matematika Doc. Name: SNMPTN2012MATDAS999 Version : 2013-04 halaman 1 01. Jika a dan b adalah bilangan bulat positif yang memenuhi ab = 220 - 219, maka nilai a+b adalah …. (A) 3 (B) 7 (C) 19 (D) 21 (E) 23 02. Jika 4log3 = k , maka 2log27 adalah … (A) k 6 (B) (C) (D) (E) k 6k 6 k6 k 03. Jika p+1 dan p-1 adalah akar-akar persamaan x2 - 4x + a = 0, maka nilai a adalah …. (A) 0 (B) 1 (C) 2 (D) 3 (E) 4 04. Jika f adalah fungsi kuadrat yang grafiknya melalui titik (1,0), (4,0), dan (0,-4), maka nilai f(7) adalah …. (A) -16 (B) -17 (C) -18 (D) -19 (E) -20 Kunci dan pembahasan soal ini bisa dilihat di www.zenius.net dengan memasukkan kode 2429 ke menu search. Copyright © 2012 Zenius Education SNMPTN 2012 Matematika, Kode Soal doc. Name: SNMPTN2011MATDAS999 version : 2013-04 | halaman 2 05. Semua nilai x yang memenuhi (x + 3)(x - 1) ≥ (x - 1) adalah (A) 1 ≤ x ≤ 3 (B) x ≤ -2 atau x ≥ 1 (C) -3 ≤ x ≤ -1 (D) -2 ≥ x atau x ≥ 3 (E) -1 ≥ x atau x ≥ 3 06. Jika 2x - z = 2, x + 2y = 4, dan y + z = 1, maka nilai 3x + 4y + z adalah …. (A) 4 (B) 5 (C) 6 (D) 7 (E) 8 07. Jika diagram batang di bawah ini memperlihatkan frekuensi kumulatif hasil tes matematika siswa kelas XII, maka persentase siswa yang memperoleh nilai 8 adalah…. (A) (B) (C) (D) (E) 12 % 15 % 20 % 22 % 80 % Kunci dan pembahasan soal ini bisa dilihat di www.zenius.net dengan memasukkan kode 2429 ke menu search. Copyright © 2012 Zenius Education SNMPTN 2012 Matematika, Kode Soal doc. Name: SNMPTN2011MATDAS999 version : 2013-04 | halaman 3 08. Ani telah mengikuti tes matematika sebanyak n kali. Pada tes berikutnya ai memperoleh nilai 83 sehingga nilai rata-rata Ani aalah 80, tetapi jika nilai tes tersebut adalah 67, maka rata-ratanya adalah 76. Nilai n adalah …. (A) 2 (B) 3 (C) 4 (D) 5 (E) 6 09. Nilai maksimum fungsi objektif (tujuan) f(x,y) = 3x + 2y dengan kendala x + 2y ≤ 12, x ≥ 2, dan y ≥ 1 adalah …. (A) 16 (B) 18 (C) 32 (D) 36 (E) 38 10. Jika dan , maka determinan matriks AB - C adalah …. (A) -5 (B) -4 (C) 5 (D) 6 (E) 7 11. Agar tiga bilangan a + 2, a - 3, a - 4 merupakan barisan aritmatika, maka suku ke dua harus ditambah dengan …. (A) -3 (B) -2 (C) -1 (D) 1 (E) 2 Kunci dan pembahasan soal ini bisa dilihat di www.zenius.net dengan memasukkan kode 2429 ke menu search. Copyright © 2012 Zenius Education SNMPTN 2012 Matematika, Kode Soal doc. Name: SNMPTN2011MATDAS999 version : 2013-04 | halaman 4 12. Jika suku pertama barisan aritmatika adalah -2 dengan beda 3, Sn adalah jumlah n suku pertama deret aritmatika tersebut, dan Sn+2 - Sn = 65, maka nilai n adalah …. (A) 11 (B) 12 (C) 13 (D) 14 (E) 15 13. Jika suatu persegi dengan sisi satu satuan dibagi menjadi 5 persegi panjang dengan luas yang sama seperti ditunjukkan pada gambar di bawah ini, maka panjang ruas garis AB adalah … (A) 3 5 (B) 2 3 (C) 2 5 (D) (E) 1 5 1 5 14. Di suatu kandang tedapat 40 ekor ayam, 15 ekor diantaranya jantan. Di antara ayam jantan tersebut, 7 ekor berwarna putih. Jika banyak ayam berwarna putih adalah 22 ekor, maka banyak ayam betina yang tidak berwarna putih adalah … (A) 5 (B) 7 (C) 8 (D) 10 (E) 15 Kunci dan pembahasan soal ini bisa dilihat di www.zenius.net dengan memasukkan kode 2429 ke menu search. Copyright © 2012 Zenius Education SNMPTN 2012 Matematika, Kode Soal doc. Name: SNMPTN2011MATDAS999 version : 2013-04 | halaman 5 15. Jika f(x) = ax + 3, a ≠ 0 dan f-1 (f-1(9)) = 3, maka nilai a2 + a + 1 adalah … (A) 11 (B) 9 (C) 7 (D) 5 (E) 3 Kunci dan pembahasan soal ini bisa dilihat di www.zenius.net dengan memasukkan kode 2429 ke menu search. Copyright © 2012 Zenius Education

Soal-Soal dan Pembahasan Matematika IPA SNMPTN 2012 ...

Soal-Soal dan Pembahasan Matematika IPA SNMPTN 2012 Tanggal Ujian: 13 Juni 2012 1. Lingkaran (x + 6)2 + (y + 1)2 = 25 menyinggung garis y = 4 di titik... A. ( -6, 4 ) B. ( 6 , 4) C. ( -1, 4 ) D. ( 1, 4 ) E. ( 5 , 4 ) Jawab: BAB XI Lingkaran Masukkan nilai y=4 pada persamaan (x + 6)2 + (4 + 1)2 = 25 (x + 6)2 = 25 – 25 = 0 x = -6 Didapat titik x = -6 dan y = 4  (-6,4) Jawabannya A 2. Jika 2x3 – 5x2 – kx + 18 dibagi x - 1 mempunyai sisa 5, maka nilai k adalah... A. -15 B. -10 C. 0 D. 5 E. 10 Jawab: BAB XII Suku Banyak Metoda Horner x3 x= 1 2 x2 x -k 18 2 2 -5 -3 -3 - k -3 ( -3- k) + = kalikan dengan x =1 (15 – k)  sisa =5 15 – k = 5 k = 15 – 5 = 10 Jawabannya E www.belajar-matematika.com 1 3. Luas daerah yang dibatasi oleh kurva y = x2, y = 1, dan x = 2 adalah... A. ∫ (1 − B. ∫ ( ) C. ∫ ( − 1) − 1) D. ∫ (1 − Jawab BAB XVI Integral E. ∫ ( ) − 1) Buat sketsa gambar untuk mengetahui batas luas: terlihat bahwa bidang luasnya (arsiran) bagian atasnya adalah y = x 2 dan bagian bawahnya y = 1 dengan dibatasi oleh batas atas x = 2 dan batas bawah x =1. Dalam notasi integralnya : b ∫ ( b b a a a L =  y2 dx -  y1 dx =  ( y 2  y1) dx − 1) Jawabannya C 4. ( ( A. B. ) ) = .... C. E. D. www.belajar-matematika.com 2 Jawab: BAB VII Trigonometri ( ( + 2 sin cos ) ) = = = =1 = 2 Jawabannya E 5. Lingkaran (x - 3)2 + (y - 4)2 = 25 memotong sumbu –x di titik A dan B. Jika P adalah titik pusat lingkaran tersebut, maka cos ∠APB = ... A. C. B. E. D. Jawab: BAB XI Lingkaran dan BAB VII Trigonometri Sketsa gambar: Lingkaran dengan pusat (3,4) APB merupakan segitiga. www.belajar-matematika.com 3 Untuk menjawab soal ini digunakan teorema di bawah ini: Aturan sinus dan cosinus C  b  a  A c B Aturan cosinus 1. a 2 = b 2 + c 2 - 2bc cos  2. b 2 = a 2 + c 2 - 2ac cos  3. c 2 = a 2 + b 2 - 2ab cos  Kita pakai rumus (3) c = AB = 6 a = b = AP = PB = √3 + 4 = √25 = 5 c 2 = a 2 + b 2 - 2ab cos P 2ab cos P = + − cos P = = = = . . . Jawabannya A 6. Grafik fungsi f(x) = ax3 – bx2 + cx + 12 naik jika.... A. b2 – 4ac < 0 dan a > 0 B. b2 – 4ac < 0 dan a < 0 C. b2 – 3ac > 0 dan a < 0 D. b2 – 3ac < 0 dan a > 0 E. b2 – 3ac < 0 dan a < 0 Jawab: BAB XV Differensial www.belajar-matematika.com 4 Syarat fungsi naik ( )>0 3ax2 - 2bx + c > 0  fungsi naik ( - , 0, + ) * variabel x2 > 0 3a > 0 a>0 *D<0 ( ) > 0 , maka tidak ada titik potong dan singgung di sb x sehingga D < 0  karena (-2b)2 – 4.3a.c < 0 4b2 – 12.a.c < 0 b2 – 3 ac < 0 didapat a > 0 dan b2 – 3 ac < 0 Jawabannya D 7. →0 = .... E. √3 √ A. -1 C. 1 B. -0 D. Jawab: XIV Limit Fungsi →0 = →0 = = = →0 →0 1 . 1. = = =1 Jawabannya C www.belajar-matematika.com

Soal dan Pembahasan Matematika IPA SNMPTN 2011

Soal-Soal dan Pembahasan SNMPTN Matematika IPA Tahun Pelajaran 2010/2011 Tanggal Ujian: 01 Juni 2011 1. Diketahui vektor u = (a, -2, -1) dan v = (a, a, -1). Jika vektor u tegak lurus pada v , maka nilai a adalah ... A. -1 B. 0 C. 1 D. 2 E. 3 Jawab: Vektor: vektor u tegak lurus pada v maka u . v = 0 u = −2 , v = −1 −2 . −1 −1 (a – 1) (a-1) = 0 maka a = 1 −1 = a2 – 2a + 1 = 0 (a - 1)2 = 0 Jawabannya adalah C 2. Pernyataan berikut yang benar adalah ... A. Jika sin x = sin y maka x = y B. Untuk setiap vektor u , v dan w berlaku u . ( v . w ) = ( u . v ). w C. Jika b  f ( x) dx = 0, maka a D. Ada fungsi f sehingga E. 1 – cos 2x = 2 cos2 x f ( x )= 0 Lim f(x) ≠ f(c) untuk suatu c xc www.belajar-matematika.com - 1 Jawab: Trigonometri, vektor, integral, limit A. Ambil nilai dimana sin x = sin y  sin α = sin (1800 – α ) ambil nilai α = 600  sin 600 = sin 1200 ; tetapi 600 ≠ 1200 Pernyataan SALAH B. Operasi u . ( v . w ) tak terdefinisi karena v . w = skalar, sedangkan u = vektor vektor . skalar = tak terdefinisi Pernyataan SALAH C. Ambil contoh cari cepat hasil dimana b  f ( x) dx = 0 ; a 1 Didapat b = 1 dan a = -1 maka f(x)= x   x dx = 0  1 terbukti : f(x) = x bukan f(x) = 0 x2 | Pernyataan SALAH D. Ambil contoh f(x) = Lim xc f(x) = Lim x 1 ( ( = ( ( ) ( )( ) = ) ( ) Lim f(x) ≠ f(c)  2 ≠ 1 xc ) ( )( ) = ) ( ) =2 Pernyataan BENAR E. 1 – cos 2x = 1 – ( 2cos2 x – 1) = 1 + 1 - 2cos2 x = 2 - 2cos2 x = 2 ( 1 – cos2 x) Pernyataan SALAH Jawabannya adalah D www.belajar-matematika.com - 2 = (1 – 1) = 0 3. Luas daerah di bawah y = -x2 +8x dan di atas y = 6x - 24 dan terletak di kuadran I adalah.... a. ∫ (− b. ∫ (− c. ∫ (− +8 ) +8 ) +8 ) d. ∫ (6 − 24) e. ∫ (6 − 24) Jawab: Integral: +∫ ( + ∫ (− + ∫ (− + ∫ (− + ∫ (− − 2 − 24) + 2 + 24) + 2 + 24) +8 ) +8 ) kuadran I titik potong kedua persamaan : y1 = y2 -x2 +8x = 6x-24 -x2 +8x - 6x+24 = 0 -x2 +2x + 24 = 0 x2 -2x - 24 = 0 (x - 6) (x+4)0 x = 6 atau x = -4  karena di kuadran I maka yang berlaku adalah x = 6  y = 6.6 – 24= 12 berada di titik (6,12) www.belajar-matematika.com - 3 L = ∫ (− = ∫ (− +8 ) +8 ) + ∫ ((− + ∫ (− Jawabannya adalah B + 8 ) − (6 − 24)) + 2 + 24) 4. sin 350 cos 400 - cos 35 sin 400 = A. cos 50 B. sin 50 C. cos 950 D. cos 750 E. sin 750 Jawab: Trigonometri: Pakai rumus: sin (A - B) = sin A cos B - cos A Sin B A= 350 ; B = 400 = sin (350 - 400) = sin -50 Cos (90 0 -  ) = sin   rumus Cos (90 0 - (-50) ) = sin -50   = -50 Cos 950 = sin -50 Jawabannya adalah C 5. Diketahui g(x) = ax2 – bx + a – b habis dibagi x – 1. Jika f(x) adalah suku banyak yang bersisa a ketika dibagi x – 1 dan bersisa 3ax + b2 + 1 ketika dibagi g(x), maka nilai a adalah...... A. -1 B. -2 C. 1 D. 2 Jawab: Suku Banyak: g(x) = ax2 – bx + a – b habis dibagi x – 1  g(1) = 0 g(1) = a . 1 – b .1 + a – b = 0 =a–b+a–b=0 2a – 2b = 0 2a = 2b  a = b karena a = b maka: g(x) = ax2 – ax + a – a = ax2 – ax www.belajar-matematika.com - 4 E. 3 f(x) dibagi dengan f(x-1) sisa a  f(1) = a f(x) dibagi dengan g(x) sisa 3ax + b2 + 1 f(x) dibagi dengan ax2 – ax sisa 3ax + b2 + 1 f(x) dibagi dengan ax(x – 1) sisa 3ax + b2 + 1 teorema suku banyak: Jika suatu banyak f(x) dibagi oleh (x- k) akan diperoleh hasil bagi H(x) dan sisa pembagian S  f(x) = (x- k) H(x) + S f(x) dibagi dengan ax(x – 1) sisa 3ax + b2 + 1 f(x) = ax (x - 1) H(x) + (3ax + b2 + 1) substitusikan nilai nol dari pembagi yaitu x = 0 dan x = 1  dari ax (x - 1) ambil x = 1  untuk x = 1 f(1) = a . 1 (1 – 1) H(0) + 3a.1 + b2 + 1 a = 0 + 3a + b2 + 1  diketahu a = b, masukkan nilai a = b a = 3a + a2 + 1 a2 + 2a + 1 = 0 (a+1)(a+1) = (a+1)2 = 0 a = -1 Jawabannya adalah A 6. Rotasi sebesar 450 terhadap titik asal diikuti dengan pencerminan terhadap y = -x memetakan titik (3,4) ke .... A. √ B. − Jawab: ,√ √ ,√ C. D. √ √ ,−√ ,−√ E. − Transformasi Geometri:  cos  Rotasi sebesar 450 terhadap titik asal =   sin    sin    cos     0  1 pencerminan terhadap y = -x    1 0     www.belajar-matematika.com - 5 √ ,√

The ULTIMATE Power Adder® for the 1999-2010 Suzuki Hayabusa

14801 W. 114th Terrace, Lenexa KS 66215 • PH: 913.338.2886 • FX: 913.338. 2879 • www.ProCharger.com. BOLT ON. 140+. 2/11. The ULTIMATE Power Adder ... The ULTIMATE Power Adder® for the 1999-2010 Suzuki Hayabusa Specializing in building customized, high-performance motorcycles, this DAS-developed Stage 1 supercharger kit utilizes a highly-efficient ProCharger C-1 self-contained supercharger for maximum forced-induction power and performance. DAS Stage I Kit includes: ProCharger C-1 supercharger Intake Charge tube Full exhaust system Intank pump FMU K&N air cleaner DAS Performance Clutch springs Stage I MSRP: $6,599 Hose, clamp and misc hardware This same C-1 supercharger and drive system is capable of supporting even higher HP levels with additional engine and fuel system modifications. Stage 1: 240-275 rwhp Stage 2: 275-350 rwhp Stage 3: 350-550+ rwhp DAS Performance dasperformance.com 1901 Bridge Street Dracut, MA 01826 978/453-0807 14801 W. 114th Terrace, Lenexa KS 66215 • PH: 913.338.2886 • FX: 913.338.2879 • www.ProCharger.com 2/11

Grinding Machines - Tool, Die & Machining Association of Wisconsin

Grinding Machines Module Outcome Summary Information Instructional Area Machine Tool Instructional Level Apprentice Organization WTCS-Wisconsin Technical College System, State Machine Tool Apprenticeship Advisory Committee Development Date 11/07/2001 Course Description This module focuses on the terminology, construction and operations of grinding machines in the metalworking industry. Be aware that in-depth information regarding cutting tools, hardware and hand tools will be addressed in their own modules. Efforts shoud be made to reference information found in other modules in order to assist the apprentice in the application and assimilation of information. Competencies 1. Advocate safe grinding machine practices Conditions and Criteria Competence will be demonstrated: • by defending a friend and fellow machinist who was injured by NOT following safety precautions Criteria - Performance will be satisfactory when: • learner lists at least 10 safety precautions related to grinding machines • learner can cite at least 5 potential hazards related to grinding machines • learner explains the importance of good shop keeping procedures Learning objectives What you will learn as you master the competency: a. List and explain precautions for protection of : eye, ears, hands, fingers, feet b. Identify specific safety violations c. Explain the ways in which clothing can be a source of hazard near a grinding machine d. Describe how you would respond to a potentially unsafe situation or condition e. Explain the possible effects of NOT completing specific shop keeping practices f. Describe shopkeeping practices outlined in the text g. Relate a safety "war" story 2. Analyze machine tool capabilities by type and construction Conditions and Criteria Competence will be demonstrated: • justify the choice of grinding machine for a given operation Criteria - Performance will be satisfactory when: • justification addresses multiple machine components (wheel size, size and style of work area, spindle location etc.) • justification follows a logical sequence • justification incorporates safe work practices Learning objectives What you will learn as you master the competency: a. Identify the major components of a grinding machine b. Identify the major types of grinding machines (internal, surface, cylindrical, tool and cutter, etc) c. Identify various machining operations performed on a grinding machine (slots, profile, taper, etc.) d. Review the safety concerns related to grinding machines e. Recognize the need for following recommended lubrication and maintenance schedules 3. Distinguish properties of abrasives Conditions and Criteria You will demonstrate your competence: • justify the selection of an abrasive for a given operation Your performance will be successful when: • justification incorporates safe grinding practices • justification recognizes efficiency in application • justification recognizes the properties of the abrasive Learning objectives What you will learn as you master the competency: a. Identify natural abrasives b. Identify synthetic abrasives c. Compare the general applications of natural and synthetic abrasives d. Characterize the importance of grain properties in grinding applications 4. Select the grinding wheel Conditions and Criteria You will demonstrate your competence: • justify the selection of a grinding wheel for a given piece part and/or operation Your performance will be successful when: • justification incorporates safe grinding practices • justification recognizes efficiency of application • justification recognizes factors involved in selection (piece part material and hardness, finish requirement, etc.) o justification incorporates information regarding the selection of wheel components Learning objectives What you will learn as you master the competency: a. Review safety concerns specific to grinding wheels b. Review types and styles of grinding wheels c. Recognize factors affecting wheel selection d. Identify the components of a grinding wheel (grit size, bond, grade, structure) e. Explain the purpose of the standard wheel symbol and marking system used in industry f. Review speed and feed applications to a variety of grinding machine applications g. Explain the process of balancing a grinding wheel h. Explain the process of truing a grinding wheel i. Differentiate between truing and dressing a grinding wheel

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