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KUNCI JAWABAN PENELITIAN KETERAMPLAN MENULIS. Yogyakarta, 02. 05. 2012. Liebe meine Freundin, wie geht es dir? Ich hoffe, daß es dir gut geht. INSTRUMEN PENELITIAN KETERAMPILAN MENULIS BAHASA JERMAN Buatlah surat sederhana dalam bahasa Jerman yang ditujukan kepada temanmu. Isi surat menceritakan tentang pengalamanmu pergi ke Bioskop. Perhatikan komponen-komponen surat berikut ini. Salam pembuka, pembuka surat, isi surat, penutup surat.( Anrede, Einführung, Inhalt, Schluß ) Poin-poin ini akan membantumu dalam menulis surat. 1. ins Kino gehen 2. am Wochenende/ in den Ferien/ am Sonntag/ am Montag/ 3. mit dem Fahrrad/ Motorrad/Auto/ Bus/ mit dem Taxi 4. mit meinen Eltern/ mit meinem Freund/ mit meiner Freundin/ allein 5. ins Kino Empire XXI/ ins Kino 21 6. Horor/ Liebe/ Komödie/ Aktion 7. interessant/ wunderbar 92 KUNCI JAWABAN PENELITIAN KETERAMPLAN MENULIS Yogyakarta, 02. 05. 2012 Liebe meine Freundin, wie geht es dir? Ich hoffe, daß es dir gut geht. Was machst du da? Am Wochenende gehe ich ins Kino. Ich fahre mit dem Auto. Ich fahre mit meinen Eltern ins Kino, denn am Wochenende heben sie keine Arbeit. Wir fahren ins Kino Empire XXI. Dort gibt es viele Filme z.B. Horor, Liebe, Komödie oder Aktion. Wir sehen Aktionfilm und ich finde den Film wunderbar. Und du? Was sind deine Aktivitäten am Wochenende? Schreib bald! Viele Grȕß e Bina Kundhini
The Blossom Fertility and IVF Centre aims to reduce the stress and hassle associated with infertility treatment and investigations by offering a one-stop fertility diagnostic and treatment service for infertile couples. The Centre offers state-of-the-art class 10000 IVF laboratory and equipments, and specialist clinical, scientific and nursing care. Excellent IVF success rates are achieved for most types of fertility treatment. Our expertise in infertility treatment and cutting edge IVF technology has helped majority of our patients achieve pregnancy.Start Realising dream of your child today by contacting Specialist of Male Infertility Diagnosis & Treatment at Blossom Fertility and IVF Centre ,Sutaria Building Opp.Bahumali Building,Nanpura, Surat-395003,Gujarat,INDIA or http://www.youtube.com/user/blossomivfindia or call on +919979946222 or just logon http://www.blossomivfindia.com or email at email@example.com
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Program Description The Florida Bright Futures Scholarship Program establishes three lottery-funded scholarships to reward Florida high school graduates for high academic achievement. The Florida Bright Futures Scholarship Program is comprised of the following three awards: • Florida Academic Scholars (FAS) award including Academic Top Scholars (ATS) award • Florida Medallion Scholars (FMS) award • Florida Gold Seal Vocational Scholars (GSV) award financial aid office or admissions office of the institution the student plans to attend. • Not owe a repayment or be in default under any state or federal grant, loan, or scholarship program unless satisfactory arrangements to repay have been made. • Receive if awarded, as an Academic Top Scholar (ATS), an additional cost per credit hour award established by the Florida Legislature in the General Appropriations Act in addition to the Florida Academic Scholars award. The ATS awardee is announced by the Florida Department of Education before the end of the fall term after all term one disbursements are reported. The ATS is awarded to the Florida Academic Scholar with the highest academic ranking in each county (based on the product of multiplying the Bright Futures GPA and the highest qualifying SAT/ACT test score). For current year award amounts visit - www.FloridaStudentFinancialAid.org/SSFAD/bf/awardamt.htm. • NEW - Submission of a Free Application for Federal Student Aid (FAFSA) is NO LONGER required; however, students are encouraged to submit the FAFSA to learn of potential eligibility for additional state and federal aid. Visit the website at www. fafsa.ed.gov for online processing. Applying for an Award For Initial Eligibility the student will: • Submit a fully completed error free Initial Student Florida Financial Aid Application during the last year in high school (after December 1 and prior to graduation) available online at www.FloridaStudentFinancialAid.org (select State Grants, Scholarships & Applications, then Apply Here). The application gives the Florida Department of Education (FDOE) permission to evaluate the student’s high school transcript and standardized test scores for eligibility for a Bright Futures Scholarship and other state scholarships and grants. • Apply during the last year in high school, before graduation, or forfeit all future eligibility for a Bright Futures Scholarship. ...
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The Tennessee Trail of Tears story is one of removal camps and detachment routes. Cherokee driven from their homes in Georgia and North Carolina arrived in Tennessee, where they waited to be organized into “detachments” to take them to Indian Territory (present-day Oklahoma), a home they never wanted. Even so, Tennessee’s legacy today remains rich in Cherokee culture. At the time the Treaty of New Echota was signed, southeast Tennessee was not only the location of the seat of the Cherokee government in Red Clay, but also the home of about 2,500 Cherokee. Prominent leaders Hair Principal Chief John Ross Conrad, James Brown, 1828-1866 Jesse Bushyhead, Lewis Ross, and Principal Chief John Ross all had homes in Tennessee. They lived in communities scattered across the hills and valleys and along the rivers and creeks. Most Cherokee farmed the fertile soils. Some owned prosperous plantations, stores, taverns, and ferries. Throughout the years, several mission schools, such as Brainerd, near Chattanooga, provided a place for Cherokee children to learn to read and write in English and to attend Christian church services. In many respects, Cherokee Tennessee Trail of Tears The “Sun Circle” at Ross’s Landing, Chattanooga Artwork by Harry Fenn The circular Cherokee design to the left symbolizes the holy sun in the form of sacred fire sent by the Creator. The central cross depicts the four logs that keep the sacred fire alive. It is said that the Cherokee will survive as long as the sacred fire burns. Ferry at Chattanooga In 1816, brothers John and Lewis Ross established the settlement of Ross’s Landing. It consisted of a ferry, warehouse, and ferry landing site We are now about to take our final leave and kind farewell to our native land the country that the Great Spirit gave our Fathers, we are on the eve of leaving that Country that gave us birth. It is the land of our fathers…our sons, and it is (with sorrow) that we are forced by the authority of the white man to quit the scenes of our childhood, but stern necessity says we must go, and we bid a final farewell to it and all we hold dear East of the Father of Waters, the Majestic Mississippi -Letter by George Hicks Dated November 4, 1838 to John Ross Traveling through Tennessee The detachment of the people are very loth [sic] to go on, and unusually slow in preparing for starting each morning. I am not surprised at this because they are moving not from choice to an unknown region not desired by them. Fort Cass 1838 historic map of the Fort Cass area Highlighted in blue are the removal camps that were spread across the valley. communities did not differ much from those of their American neighbors. In 1838, though, Cherokee life was about to change. Beginning in late May 1838, thousands of Cherokee, enslaved African Americans, and Creek were taken from their homes by troops and held at removal camps near one of three emigrating depots. Two of these camps were located in the vicinity of Cherokee communities in Tennessee: Ross’s Landing, now known as Chattanooga, and Fort Cass in presentday Charleston. During removal, Fort Cass served as the center for the largest emigrating depot. Removal camps in this area were spread out over a 12- by 4-mile area, extending from Charleston southward. Approximately 7,000 Cherokees were held at these camps prior to their departure to Indian Territory, but poor conditions at the camps led to rapid outbreaks of disease, and many perished before the journey began. How many more families would lose their loved ones before reaching their new homes? -Detachment Conductor Elijah Hicks, October 24, 1838 The Cherokee used many different routes to reach their new home in the West—most started in Tennessee. In June, three groups of Cherokee left Ross’s landing to begin their journey to Indian Territory. Dire conditions, disease, and deaths plagued the last two groups. As a result, Principal Chief John Ross and other Cherokee leaders petitioned the US government to allow the Cherokee to control the remainder of their removal. Permission was granted and the remaining Cherokee were organized into detachments of about 1,000 each.
Soal-Soal dan Pembahasan SNMPTN Matematika IPA Tahun Pelajaran 2010/2011 Tanggal Ujian: 01 Juni 2011 1. Diketahui vektor u = (a, -2, -1) dan v = (a, a, -1). Jika vektor u tegak lurus pada v , maka nilai a adalah ... A. -1 B. 0 C. 1 D. 2 E. 3 Jawab: Vektor: vektor u tegak lurus pada v maka u . v = 0 u = −2 , v = −1 −2 . −1 −1 (a – 1) (a-1) = 0 maka a = 1 −1 = a2 – 2a + 1 = 0 (a - 1)2 = 0 Jawabannya adalah C 2. Pernyataan berikut yang benar adalah ... A. Jika sin x = sin y maka x = y B. Untuk setiap vektor u , v dan w berlaku u . ( v . w ) = ( u . v ). w C. Jika b f ( x) dx = 0, maka a D. Ada fungsi f sehingga E. 1 – cos 2x = 2 cos2 x f ( x )= 0 Lim f(x) ≠ f(c) untuk suatu c xc www.belajar-matematika.com - 1 Jawab: Trigonometri, vektor, integral, limit A. Ambil nilai dimana sin x = sin y sin α = sin (1800 – α ) ambil nilai α = 600 sin 600 = sin 1200 ; tetapi 600 ≠ 1200 Pernyataan SALAH B. Operasi u . ( v . w ) tak terdefinisi karena v . w = skalar, sedangkan u = vektor vektor . skalar = tak terdefinisi Pernyataan SALAH C. Ambil contoh cari cepat hasil dimana b f ( x) dx = 0 ; a 1 Didapat b = 1 dan a = -1 maka f(x)= x x dx = 0 1 terbukti : f(x) = x bukan f(x) = 0 x2 | Pernyataan SALAH D. Ambil contoh f(x) = Lim xc f(x) = Lim x 1 ( ( = ( ( ) ( )( ) = ) ( ) Lim f(x) ≠ f(c) 2 ≠ 1 xc ) ( )( ) = ) ( ) =2 Pernyataan BENAR E. 1 – cos 2x = 1 – ( 2cos2 x – 1) = 1 + 1 - 2cos2 x = 2 - 2cos2 x = 2 ( 1 – cos2 x) Pernyataan SALAH Jawabannya adalah D www.belajar-matematika.com - 2 = (1 – 1) = 0 3. Luas daerah di bawah y = -x2 +8x dan di atas y = 6x - 24 dan terletak di kuadran I adalah.... a. ∫ (− b. ∫ (− c. ∫ (− +8 ) +8 ) +8 ) d. ∫ (6 − 24) e. ∫ (6 − 24) Jawab: Integral: +∫ ( + ∫ (− + ∫ (− + ∫ (− + ∫ (− − 2 − 24) + 2 + 24) + 2 + 24) +8 ) +8 ) kuadran I titik potong kedua persamaan : y1 = y2 -x2 +8x = 6x-24 -x2 +8x - 6x+24 = 0 -x2 +2x + 24 = 0 x2 -2x - 24 = 0 (x - 6) (x+4)0 x = 6 atau x = -4 karena di kuadran I maka yang berlaku adalah x = 6 y = 6.6 – 24= 12 berada di titik (6,12) www.belajar-matematika.com - 3 L = ∫ (− = ∫ (− +8 ) +8 ) + ∫ ((− + ∫ (− Jawabannya adalah B + 8 ) − (6 − 24)) + 2 + 24) 4. sin 350 cos 400 - cos 35 sin 400 = A. cos 50 B. sin 50 C. cos 950 D. cos 750 E. sin 750 Jawab: Trigonometri: Pakai rumus: sin (A - B) = sin A cos B - cos A Sin B A= 350 ; B = 400 = sin (350 - 400) = sin -50 Cos (90 0 - ) = sin rumus Cos (90 0 - (-50) ) = sin -50 = -50 Cos 950 = sin -50 Jawabannya adalah C 5. Diketahui g(x) = ax2 – bx + a – b habis dibagi x – 1. Jika f(x) adalah suku banyak yang bersisa a ketika dibagi x – 1 dan bersisa 3ax + b2 + 1 ketika dibagi g(x), maka nilai a adalah...... A. -1 B. -2 C. 1 D. 2 Jawab: Suku Banyak: g(x) = ax2 – bx + a – b habis dibagi x – 1 g(1) = 0 g(1) = a . 1 – b .1 + a – b = 0 =a–b+a–b=0 2a – 2b = 0 2a = 2b a = b karena a = b maka: g(x) = ax2 – ax + a – a = ax2 – ax www.belajar-matematika.com - 4 E. 3 f(x) dibagi dengan f(x-1) sisa a f(1) = a f(x) dibagi dengan g(x) sisa 3ax + b2 + 1 f(x) dibagi dengan ax2 – ax sisa 3ax + b2 + 1 f(x) dibagi dengan ax(x – 1) sisa 3ax + b2 + 1 teorema suku banyak: Jika suatu banyak f(x) dibagi oleh (x- k) akan diperoleh hasil bagi H(x) dan sisa pembagian S f(x) = (x- k) H(x) + S f(x) dibagi dengan ax(x – 1) sisa 3ax + b2 + 1 f(x) = ax (x - 1) H(x) + (3ax + b2 + 1) substitusikan nilai nol dari pembagi yaitu x = 0 dan x = 1 dari ax (x - 1) ambil x = 1 untuk x = 1 f(1) = a . 1 (1 – 1) H(0) + 3a.1 + b2 + 1 a = 0 + 3a + b2 + 1 diketahu a = b, masukkan nilai a = b a = 3a + a2 + 1 a2 + 2a + 1 = 0 (a+1)(a+1) = (a+1)2 = 0 a = -1 Jawabannya adalah A 6. Rotasi sebesar 450 terhadap titik asal diikuti dengan pencerminan terhadap y = -x memetakan titik (3,4) ke .... A. √ B. − Jawab: ,√ √ ,√ C. D. √ √ ,−√ ,−√ E. − Transformasi Geometri: cos Rotasi sebesar 450 terhadap titik asal = sin sin cos 0 1 pencerminan terhadap y = -x 1 0 www.belajar-matematika.com - 5 √ ,√
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