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DonRay Petroleum, LLC, a privately held oil and gas company located in Oklahoma City, today announced the completion of the DRP Grace #25 joint venture well in Noble, County, Okla. Visit: http://donraypetroleum.com
S90 Electric Solid Top, electric oven, island, 1 side operation – 208 V S90 Electric Solid Top, electric oven, island, 1 side operation – 240 V Optional Accessories Short Form Specification Item No. ___________________________________ Unit to be Electrolux S90 Heavy Duty Electric Solid Top on Electric Oven. Electrical characteristics to be ___ 208 V or ___ 240 V three phase. Unit to be installed in central island type installations with operations from one side. Unit shall have joint free large cooking surface with 4 heating areas with individual temperature settings for each zone from as low as 212 °F (100 °C) to as high as 842 °F (450 °C). Large flat cooking surface made of mild steel permits the use of a number of various sized pots and pans, all easily moved across the surface without lifting. Body and open base of unit entirely in 304 stainless steel. Unit shall have heavy duty 304 stainless steel internal frame. Extra strength work top in heavy duty 0.118” (3 mm) stainless steel. “Lasertec” connection system permits units to be connected to each other creating a seamless work top. Set 4 castors (2 with brake). Left side stainless steel 0.118″ (3 mm) panel. Right side stainless steel 0.118″ (3 mm) panel. 5″ (130 mm) portioning shelf. 7.8″ (200 mm) portioning shelf. All round stainless steel plinth. Shelf for open base. Shelf fixation kit for open base. Polinox steel wool for solid top cleaning. Covered by Electrolux Platinum Star® Service Program two-year parts and one-year labor warranty, installation start-up and performance check-up after one year from installation. Approval: ___________________________________________ Electrolux Professional, Inc. www.electroluxusa.com/professional 3225 SW 42nd Street, Fort Lauderdale, Florida, 33312 • Telephone Number: 866-449-4200 • Fax Number: 954-327-6789 Modular Cooking Range Line S90 Electric Solid Top on Electric Oven, Island, 1 Side Modular Cooking Range Line S90 Electric Solid Top on Electric Oven, Island, 1 Side • Unit for island type installation with operation by chef from one side (nobs only on one side of the console). • 4 high powered heating electric zones. • Solid top made of mild steel, smooth pore-free and easy to clean. • 4 heating zones independently controlled. • Surface temperature can be regulated with two power levels up to 842 °F (450 °C) for a very high degree of accuracy. • Joint free large cooking surface. • Rapid heat up of the plate and continuously ready for use. • Setting different temperature zones provides a temperature gradient over the plate for different cooking needs. • Various sizes of pans can be used at the same time due to large surface area with no intermediate sectors. • Pans can easily be moved from one area to another without lifting. • Base compartment consists of an electric heated standard oven for base heat. Ovens equipped with one Stainless steel grid and one enameled baking tray....
Establishing oneself in the competitive world is not easy as it seems. But personalities like Michael Wellman Jr. Alaska has accomplished himself in the construction industry by launching his construction venture- Vertical Superstructures.
In addition to ideal insurance plans for your own home, nevertheless, the real failure or success of any job are going to joint located on the home remodeling designer and installer that you just go with. If you choose a good quality licensed contractor, will be possible to sleep confident that a operate may be undertaken adequately at first you could a project that's going to allow you to get time of exhilaration.It requires a couple of make an effort to provide you a quality constructor, but the motivation may decrease the likelyhood that you will find complications all through the creation. You should also employ a more beneficial possible evading devious tradesman and even reimbursement differences. Initially, enquire just about any good friends, close relatives, or sometimes co-workers who might possibly have not too long ago previously had very close give good results managed
This is not something which can be done by one person. It is a joint effort which all the members in the building should put in and this can be through the waste management processes.
Soal-Soal dan Pembahasan SNMPTN Matematika IPA Tahun Pelajaran 2010/2011 Tanggal Ujian: 01 Juni 2011 1. Diketahui vektor u = (a, -2, -1) dan v = (a, a, -1). Jika vektor u tegak lurus pada v , maka nilai a adalah ... A. -1 B. 0 C. 1 D. 2 E. 3 Jawab: Vektor: vektor u tegak lurus pada v maka u . v = 0 u = −2 , v = −1 −2 . −1 −1 (a – 1) (a-1) = 0 maka a = 1 −1 = a2 – 2a + 1 = 0 (a - 1)2 = 0 Jawabannya adalah C 2. Pernyataan berikut yang benar adalah ... A. Jika sin x = sin y maka x = y B. Untuk setiap vektor u , v dan w berlaku u . ( v . w ) = ( u . v ). w C. Jika b f ( x) dx = 0, maka a D. Ada fungsi f sehingga E. 1 – cos 2x = 2 cos2 x f ( x )= 0 Lim f(x) ≠ f(c) untuk suatu c xc www.belajar-matematika.com - 1 Jawab: Trigonometri, vektor, integral, limit A. Ambil nilai dimana sin x = sin y sin α = sin (1800 – α ) ambil nilai α = 600 sin 600 = sin 1200 ; tetapi 600 ≠ 1200 Pernyataan SALAH B. Operasi u . ( v . w ) tak terdefinisi karena v . w = skalar, sedangkan u = vektor vektor . skalar = tak terdefinisi Pernyataan SALAH C. Ambil contoh cari cepat hasil dimana b f ( x) dx = 0 ; a 1 Didapat b = 1 dan a = -1 maka f(x)= x x dx = 0 1 terbukti : f(x) = x bukan f(x) = 0 x2 | Pernyataan SALAH D. Ambil contoh f(x) = Lim xc f(x) = Lim x 1 ( ( = ( ( ) ( )( ) = ) ( ) Lim f(x) ≠ f(c) 2 ≠ 1 xc ) ( )( ) = ) ( ) =2 Pernyataan BENAR E. 1 – cos 2x = 1 – ( 2cos2 x – 1) = 1 + 1 - 2cos2 x = 2 - 2cos2 x = 2 ( 1 – cos2 x) Pernyataan SALAH Jawabannya adalah D www.belajar-matematika.com - 2 = (1 – 1) = 0 3. Luas daerah di bawah y = -x2 +8x dan di atas y = 6x - 24 dan terletak di kuadran I adalah.... a. ∫ (− b. ∫ (− c. ∫ (− +8 ) +8 ) +8 ) d. ∫ (6 − 24) e. ∫ (6 − 24) Jawab: Integral: +∫ ( + ∫ (− + ∫ (− + ∫ (− + ∫ (− − 2 − 24) + 2 + 24) + 2 + 24) +8 ) +8 ) kuadran I titik potong kedua persamaan : y1 = y2 -x2 +8x = 6x-24 -x2 +8x - 6x+24 = 0 -x2 +2x + 24 = 0 x2 -2x - 24 = 0 (x - 6) (x+4)0 x = 6 atau x = -4 karena di kuadran I maka yang berlaku adalah x = 6 y = 6.6 – 24= 12 berada di titik (6,12) www.belajar-matematika.com - 3 L = ∫ (− = ∫ (− +8 ) +8 ) + ∫ ((− + ∫ (− Jawabannya adalah B + 8 ) − (6 − 24)) + 2 + 24) 4. sin 350 cos 400 - cos 35 sin 400 = A. cos 50 B. sin 50 C. cos 950 D. cos 750 E. sin 750 Jawab: Trigonometri: Pakai rumus: sin (A - B) = sin A cos B - cos A Sin B A= 350 ; B = 400 = sin (350 - 400) = sin -50 Cos (90 0 - ) = sin rumus Cos (90 0 - (-50) ) = sin -50 = -50 Cos 950 = sin -50 Jawabannya adalah C 5. Diketahui g(x) = ax2 – bx + a – b habis dibagi x – 1. Jika f(x) adalah suku banyak yang bersisa a ketika dibagi x – 1 dan bersisa 3ax + b2 + 1 ketika dibagi g(x), maka nilai a adalah...... A. -1 B. -2 C. 1 D. 2 Jawab: Suku Banyak: g(x) = ax2 – bx + a – b habis dibagi x – 1 g(1) = 0 g(1) = a . 1 – b .1 + a – b = 0 =a–b+a–b=0 2a – 2b = 0 2a = 2b a = b karena a = b maka: g(x) = ax2 – ax + a – a = ax2 – ax www.belajar-matematika.com - 4 E. 3 f(x) dibagi dengan f(x-1) sisa a f(1) = a f(x) dibagi dengan g(x) sisa 3ax + b2 + 1 f(x) dibagi dengan ax2 – ax sisa 3ax + b2 + 1 f(x) dibagi dengan ax(x – 1) sisa 3ax + b2 + 1 teorema suku banyak: Jika suatu banyak f(x) dibagi oleh (x- k) akan diperoleh hasil bagi H(x) dan sisa pembagian S f(x) = (x- k) H(x) + S f(x) dibagi dengan ax(x – 1) sisa 3ax + b2 + 1 f(x) = ax (x - 1) H(x) + (3ax + b2 + 1) substitusikan nilai nol dari pembagi yaitu x = 0 dan x = 1 dari ax (x - 1) ambil x = 1 untuk x = 1 f(1) = a . 1 (1 – 1) H(0) + 3a.1 + b2 + 1 a = 0 + 3a + b2 + 1 diketahu a = b, masukkan nilai a = b a = 3a + a2 + 1 a2 + 2a + 1 = 0 (a+1)(a+1) = (a+1)2 = 0 a = -1 Jawabannya adalah A 6. Rotasi sebesar 450 terhadap titik asal diikuti dengan pencerminan terhadap y = -x memetakan titik (3,4) ke .... A. √ B. − Jawab: ,√ √ ,√ C. D. √ √ ,−√ ,−√ E. − Transformasi Geometri: cos Rotasi sebesar 450 terhadap titik asal = sin sin cos 0 1 pencerminan terhadap y = -x 1 0 www.belajar-matematika.com - 5 √ ,√
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LOW SPEED VIBRATION AND DRIVE SHAFT ANGLES Cardan (cross) type universal joint operation is typically designed to be in a range of 1 to 3°, figure 1. A cardan type joint can operate for short periods of time at angles up to approximately eight degrees. Angles that are not within the desired range will cause drive line vibration and significantly shorten the life of the universal joint. Vibration that is created by incorrect u-joint angles is usually most noticeable at low speeds, under 40 mph., under load or acceleration. If a problem with u-joint angle is suspected perform the following basic inspection procedures. 1. Rotate the drive shaft to check for binding, or misalignment of the cross or bearing cups. 2. Check that all surfaces are clean. 3. Check the condition of the motor and transmission mounts. Broken mounts are a frequent cause of drive shaft vibration and are often overlooked. If these conditions are satisfactory a preliminary check of angles can be made with an inclinometer. Before attempting to measure angles ensure that tire air pressure is correct, that the vehicle is at the correct trim (chassis) height, and the ground surface is level. 1. Measure the angle of the front slip yoke by placing the inclinometer on the bottom of the bearing cup, figure 2. Position the inclinometer on the clean flat surface of the bearing cup, level the bubble and note the reading. 2. Measure the drive shaft angle, as shown, and subtract the smaller number from the greater to determine the angle. 3. Repeat the same procedure on the rear u-joint and pinion input shaft.
DRIVELINE VIBRATION AFTER U-JOINT REPLACEMENT Drive line vibration, after u-joint replacement, is usually the result of a u-joint not properly positioned, or yoke ears which are binding. In either case the problem can usually be pin pointed by articulating the drive shaft. The problem area will show itself as restricted or binding motion, fig.1. Driveline vibration can sometimes occur after after u-joint replacement when plastic injection was the original means of retention, fig.2. The replacement u-joint, even though centered, could cause the shaft to vibrate. INJECTED PLASTIC FIG.1 When drive shafts using plastic injection are assembled one of the last steps is balancing. If a u-joint is lightly off center the shaft could still run smoothly after balancing, fig.3. PLASTIC INJECTION RETENTION UNIVERSAL JOINT AND YOKE USING PLASTIC INJECTIN FOR U-JOINT RETENTION FIG.2 NOTE: MISALIGNMENT FIG.3 However, when the u-joint is replaced and "C" clips are used for retention the replacement ujoint will be in a different position. This can cause the drive shaft to become out of balance. To correct the problem the drive shaft will have to be balanced. SNAP RING ("C" CLIP) RETENTION The snap ring ("C" clip) retention design is a more conventional method of fitting the u-joint in the yoke. The grooves and ring are a fixed dimention and fit against a machined surface in the yoke, fig. 4. FIG.4 © 1994 Federal-Mogul Corporation Southfield, MI 48034 SL7-94 60M 0000 (X) Printed in U.S>A.