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VENISON RECIPES “World Class” Venison Stew 2 lb. venison steaks 2 to 3 T. Vegetable oil 6 c. hot water 2 T. Worcestershire sauce 1 T. salt 1 T. sugar 1 ½ tsp. paprika ¾ tsp. pepper Dash of cloves 4 tsp. beef bouillon 1 med. onion, thinly sliced 2 to 3 lg. carrots, cut to bite-size 2 lg. potatoes, cut to bite-size 2 bay leaves 1 sm. pkg. frozen corn 1 sm. pkg. frozen peas 8 T. cornstarch Small amount of cold water Cube venison steaks into bite-size pieces and brown in vegetable oil. In crockpot, combine browned meat, water, Worcestershire sauce, salt, sugar, paprika, pepper, cloves, beef bouillon, onion, potatoes and bay leaves. Cook for 6 hours. Add corn and peas. Cook for 1 hour. Mix cornstarch with small amount of cold water and add to stew. Simmer until stew thickens. Remove bay leaves. Venison Stroganoff 1 ½ lb. venison round steak Flour, seasoned with salt & pepper 3 T. butter 1 onion, chopped ¼ tsp. basil ¼ tsp. thyme Salt & pepper to taste 1 ¼ c. beef bouillon 1 c. sliced mushrooms 2 T. butter 2 T. flour 1 ½ tsp. prepared mustard 1 c. sour cream Parsley sprigs & pimento chunks
Phase II Diet – Pureed Foods 1. For approximately two more weeks, your new pouch will be swollen because of the surgery. You will need to eat a pureed diet with a consistency of small curd cottage cheese, baby food or applesauce. “Mashing” certain foods or “chewing very well” does not produce the correct consistency; your food must be pureed. This diet will allow the swelling to subside and will minimize the chances of food particles lodging in your stomach opening. Note: Many patients choose not to puree their food but instead eat foods that are already a pureed consistency or considered acceptable by The Surgical Treatment for Obesity staff: Plain yogurt, drinkable yogurt, small curd cottage cheese, melted cheese, refried beans, plain quick/instant oatmeal, cream of wheat, grits, farina, plain scrambled egg, liver sausage, hummus, sugar-free pudding, stage I baby foods Tip: To save time and to avoid wasting food, many people puree food and then pour it into ice cube trays, let it freeze, and then place it into plastic bags. When it is time to eat, simply microwave a few cubes and you have a quick meal. 2. Each meal should contain no more than 2 oz. (1/4 cup) of food. 3. Eat only three meals daily. Liquids must be consumed between meals only. Drinking while eating may cause the food you have consumed to move through the pouch more quickly, and may lead to overeating. Always wait at least 60 minutes after you have finished eating to begin drinking.
Roland AC Adapter Compatibility Guide Model A-30/33/37 A-300PRO A-500PRO A-500S A-800PRO AC-2/3 AC-33 AD-3/8 AD-5 AF-70 AR-100/200 ASC-10 AT-350C AW-2/3 AX-09 AX-1/7 AX-Synth Original Adapter ACA-120 PSB-120 PSB-120 PSA-120S PSB-120 PSA-120 PSB-12U PSA-120 ACF-120 BRC-120 ACI-120 PSA-120 PSB-120 PSA-120 PSB-120 ACA-120 PSB-120 New Adapter/Substitute PSA-120S Model BA-55 BA-330 BC-2 BCB-60 BD-2 BE-5/5B BF-1/3 BF-2/2B BL-1 BK-3 BK-5 BK-7M BK-9 BR-8 BR-80 BR-532/864 BR-600 BR-800 BR-900CD BR-1180/CD BR-1200CD BR-1600CD BX-4/400 BX-8/16 Original Adapter PSB-12U PSB-13U PSA-120S PSC-100 PSA-120 PSA-120 PSA-120 ACA-120 PSA-120 PSB-120 PSB-7U PSB-120 PSB-120 PSB-120 PSA-120S PSA-120 PSA-120 PSA-120S PSC-100 PSB-7U PSB-7U PSB-7U PSA-120 ACE-120 New Adapter/Substitute Model C-200 CA-30 CD-2 Original Adapter PSB-7U ACA-120 PSB-7U New Adapter/Substitute Included PSA-120S X PSA-120S PSB-120 PSB-120 PSA-120S X X X X PSA-120S X PSA-120S X Included X X X PSA-120S PSA-120S PSA-120S PSA-120S PSA-120S X X X X X X PSA-120S PSA-120S PSB-120 X X X X X PSA-120S X PSA-120S Included X X X CD-2E CD-2i CDX-1 CE-1/5/20 CE-2/2B/3 CEB-3 CF-10 CH-1 CL-50 CM-300/500 CM-32L/P/64 CN-20 CP-40 CR-1000 CR-80 CS-10 CS-1/2/3 CT-6 Cube Lite Cube Street PSB-120 PSB-120 PSB-2U PSA-120 ACA-120 ACA-120 ACI-120 PSA-120 BRA-120 ACK-120 ACB-120 ACA-120 PSA-120 PSA-120 ACI-120 ACB-120 ACA-120 PSA-120 PSD-120 PSB-120 X X X Model D-2 D-5 DB-5/33 DB-66/88/90 DC-2/3 DD-2/3/5/6/7 DD-20 DF-2 DI-1 DIF-800 DM-2/3 DN-2 DR-110 DR-202/A/E DR-3/5 DR-550/mkII DR-660 DR-670 DR-770/880 DS-1/2/3 DS-330 DSD-2/3 Duo-Capture EX Original Adapter ACI-120 ACI-120 PSA-120S PSA-120S PSA-120S PSA-120S PSA-120S PSA-120S PSA-120S ACI-120 PSA-120S PSA-120S PSA-120S PSA-120S PSA-120S PSA-120S BRA-120 PSA-120S BRC-120 PSA-120S BRA-120 PSA-120S PSB-120 New Adapter/Substitute PSB-120 PSB-120 Included X X PSB-120 X BRB-120 X BRB-120 X Model E-09 E-5 E-12/14 E-15 E-16 Original Adapter PSB-120 ACJ-120 ACN-120 ACI-120 ACN-120 New Adapter/Substitute Included X X X X X PSA-120S PSA-120S PSA-120S PSB-120 PSA-120S BRB-120 PSB-120 PSB-120 PSA-120S PSA-120S PSA-120S PSB-120 PSB-120 PSA-120S PSA-120S X X X X X X X X X X X PSB-4UREPL PSB-4UREPL PSB-120 PSB-4UREPL E-28 E-35 E-36 E-38 E-50/60 E-56/66/68 E-300 EG-101 EH-2 EH-50 EM-10/15 EM-20/25 EM-30/55 EM-303/505 ep-3/5 ep-7 ep-7mkII ep-9 ep-70 ep-75/95 ep-85 ep-90 ep-97 ep-707 ep-760 EQ-20 EXR-3 EXR-5/7/7S EXR-40/46OR ACO-120 ACJ-120 ACI-120 ACO-120 PSB-4U ACJ-120 ACJ-120 ACJ-120 PSA-120 BRA-120 ACN-120 ACO-120 ACJ-120 ACK-120 ACI-120 ACL-120 ACK-120 ACK-120 ACB-120 ACO-120 ACJ-120 ACB-120 ACJ-120 ACK-120 ACO-120 PSA-120 ACO-120 PSB-4U PSB-4U PSB-4UREPL PSB-4UREPL PSB-120 PSB-4UREPL PSB-4UREPL PSB-4UREPL PSB-4UREPL PSB-4UREPL PSA-120S BRB-120 PSB-4UREPL PSB-4UREPL PSB-4UREPL PSB-120 PSB-120 PSB-4UREPL PSB-120 PSB-120 PSB-120 PSB-4UREPL PSB-4UREPL PSB-120 PSB-4UREPL PSB-120 PSB-4UREPL PSA-120S PSB-4UREPL PSB-4UREPL PSB-4UREPL Model Fantom-Xa F-30/50 F-90/100 F-110/120 FA-66/101 FB-2 FBM-1 FC-200/300 FC-50 FDR-1 FP-2/3/4 FP-4F FP-5 FP-7/7F FP-50/80 FR-1/2/2B FR-1X/XB FR-3/S/B/BS FR-3X/XB FR-18D FRV-1 Original Adapter PSB-120 PSB-120 PSB-120 PSB-7U PSB-120 PSA-120S PSA-120 PSA-120 PSA-120 PSA-120 PSB-120 PSB-7U PSB-3U PSB-7U PSB-7U PSB-120 PSB-120 PSB-4U PSB-7U PSB-120 PSA-120S New Adapter/Substitute X X X X X X X X X X X X X X X X X X X X X X X X X X X Included X X X X X PSA-120S PSA-120S PSA-120S PSA-120S PSB-7U PSB-4UREPL X X X X X X X X X X FT-2 FW-3 FZ-2/3/5 ACA-120 PSA-120 PSA-120 PSA-120S PSA-120S PSA-120S Model GE-21 GE-6 GE-7/7B GE-10 GEB-7 GFC-50 GI-10 GI-20 GP-20 GR-09 GR-D/S GR-1 GR-20/33 GR-30 GR-55 GS-10 GT-3 GT-6/6B/8 GT-10/10B GT-100 GW-7/8 GX-700 Original Adapter BRA-120 PSA-120 ACA-120 PSA-120 PSA-120 PSA-120 ACM-120 ACI-120 PSA-120 BRA-120 PSA-120S ACI-120 BRC-120 ACI-120 PSB-120 BRC-120 BRC-120 BRC-120 PSB-120 PSB-120 PSB-120 BRC-120 New Adapter/Substitute BRB-120 PSA-120S PSA-120S PSA-120S PSA-120S PSA-120S PSA-120S PSB-120 PSA-120S BRB-120 Included X PSB-120 X X X X X X X X X X X Model HA-5 HC-2 HD-1/3 HF-2 HM-2 HM-3 HP-503 HP-505 HPD-10 HPD-15 HPD-20 HR-2 Original Adapter PSA-120 PSA-120 PSB-120 ACA-120 ACA-120 PSA-120 PSB-7U PSB-14U PSB-120 ACI-120 PSB-120 PSA-120 New Adapter/Substitute PSA-120S PSA-120S Model JM-5 JM-8 Juno-D Juno-Di Juno-G / Gi Juno-Stage Jupiter-50 JV-30/35 JV-50 Original Adapter PSB-120 PSB-7U ACI-120 PSB-120 PSB-120 PSB-120 PSB-120 ACI-120 ACK-120 New Adapter/Substitute PSB-120 X X X X Included X PSA-120S PSA-120S PSA-120S PSB-120 X X X X X PSA-120S PSB-1U PSB-120 PSB-120 Included X X X X X X X X X JV-1010 JW-50 JS-5 JS-8/10 JX-1 JX-305 ACI-120 ACK-120 BRC-120 PSB-120 BRA-120 ACI-120 PSB-120 PSB-120 Model KC-110 KF-7 Original Adapter PSB-12U PSB-3U New Adapter/Substitute Model LM-2 LM-2B LMB-3 LS-2 LVC-1N Original Adapter ACA-120 PSA-120 PSA-120 PSA-120 ACN-120 New Adapter/Substitute PSA-120S PSA-120S PSA-120S PSA-120S PSB-4UREPL Included Model M-10DX/MX M-16DX M-100FX M-660 MC-09 MC-50/mkII MC-202 MC-303 MC-307 MC-808 MD-2 ME-6/6B ME-8/8B ME-20/20B ME-25 ME-30/33 ME-50/50B ME-70 ME-X Micro-BR Micro Cube Micro Cube GX Micro Cube RX Micro Cube Bass RX Mobile Cube ML-2 MPD-4 MS-1 MSL-15 MT-100/120 MT-2 MT-200 MT-32 Original Adapter PSB-120 PSB-120 ACI-120 ACI-120 ACI-120 ACI-120 PSA-120 ACI-120 ACI-120 PSB-3U PSA-120 BRA-120 BRC-120 PSA-120 PSA-120S PSA-120 PSA-120 PSA-120S ACI-120 PSA-120 ACR-120 PSD-120 PSB-120 PSB-120 PSB-120 PSA-120 PSA-120 PSA-120 PSA-120 ACB-120 PSA-120 ACK-120 ACB-120 New Adapter/Substitute Included X X X X X X X X X X BRB-120 PSB-120 PSB-7U PSB-120 PSB-120 PSB-120 PSB-120 PSA-120S PSB-120 PSB-120 PSB-7U PSA-120S BRB-120 X X X X X X Included X X X X X PSA-120S PSA-120S PSA-120S PSB-120 PSA-120S X X X X X PSA-120S PSA-120S PSA-120S PSA-120S PSB-120 PSA-120S PSB-120 PSA-120S X X X X
Soal-Soal dan Pembahasan Matematika IPA SNMPTN 2012 Tanggal Ujian: 13 Juni 2012 1. Lingkaran (x + 6)2 + (y + 1)2 = 25 menyinggung garis y = 4 di titik... A. ( -6, 4 ) B. ( 6 , 4) C. ( -1, 4 ) D. ( 1, 4 ) E. ( 5 , 4 ) Jawab: BAB XI Lingkaran Masukkan nilai y=4 pada persamaan (x + 6)2 + (4 + 1)2 = 25 (x + 6)2 = 25 – 25 = 0 x = -6 Didapat titik x = -6 dan y = 4 (-6,4) Jawabannya A 2. Jika 2x3 – 5x2 – kx + 18 dibagi x - 1 mempunyai sisa 5, maka nilai k adalah... A. -15 B. -10 C. 0 D. 5 E. 10 Jawab: BAB XII Suku Banyak Metoda Horner x3 x= 1 2 x2 x -k 18 2 2 -5 -3 -3 - k -3 ( -3- k) + = kalikan dengan x =1 (15 – k) sisa =5 15 – k = 5 k = 15 – 5 = 10 Jawabannya E www.belajar-matematika.com 1 3. Luas daerah yang dibatasi oleh kurva y = x2, y = 1, dan x = 2 adalah... A. ∫ (1 − B. ∫ ( ) C. ∫ ( − 1) − 1) D. ∫ (1 − Jawab BAB XVI Integral E. ∫ ( ) − 1) Buat sketsa gambar untuk mengetahui batas luas: terlihat bahwa bidang luasnya (arsiran) bagian atasnya adalah y = x 2 dan bagian bawahnya y = 1 dengan dibatasi oleh batas atas x = 2 dan batas bawah x =1. Dalam notasi integralnya : b ∫ ( b b a a a L = y2 dx - y1 dx = ( y 2 y1) dx − 1) Jawabannya C 4. ( ( A. B. ) ) = .... C. E. D. www.belajar-matematika.com 2 Jawab: BAB VII Trigonometri ( ( + 2 sin cos ) ) = = = =1 = 2 Jawabannya E 5. Lingkaran (x - 3)2 + (y - 4)2 = 25 memotong sumbu –x di titik A dan B. Jika P adalah titik pusat lingkaran tersebut, maka cos ∠APB = ... A. C. B. E. D. Jawab: BAB XI Lingkaran dan BAB VII Trigonometri Sketsa gambar: Lingkaran dengan pusat (3,4) APB merupakan segitiga. www.belajar-matematika.com 3 Untuk menjawab soal ini digunakan teorema di bawah ini: Aturan sinus dan cosinus C b a A c B Aturan cosinus 1. a 2 = b 2 + c 2 - 2bc cos 2. b 2 = a 2 + c 2 - 2ac cos 3. c 2 = a 2 + b 2 - 2ab cos Kita pakai rumus (3) c = AB = 6 a = b = AP = PB = √3 + 4 = √25 = 5 c 2 = a 2 + b 2 - 2ab cos P 2ab cos P = + − cos P = = = = . . . Jawabannya A 6. Grafik fungsi f(x) = ax3 – bx2 + cx + 12 naik jika.... A. b2 – 4ac < 0 dan a > 0 B. b2 – 4ac < 0 dan a < 0 C. b2 – 3ac > 0 dan a < 0 D. b2 – 3ac < 0 dan a > 0 E. b2 – 3ac < 0 dan a < 0 Jawab: BAB XV Differensial www.belajar-matematika.com 4 Syarat fungsi naik ( )>0 3ax2 - 2bx + c > 0 fungsi naik ( - , 0, + ) * variabel x2 > 0 3a > 0 a>0 *D<0 ( ) > 0 , maka tidak ada titik potong dan singgung di sb x sehingga D < 0 karena (-2b)2 – 4.3a.c < 0 4b2 – 12.a.c < 0 b2 – 3 ac < 0 didapat a > 0 dan b2 – 3 ac < 0 Jawabannya D 7. →0 = .... E. √3 √ A. -1 C. 1 B. -0 D. Jawab: XIV Limit Fungsi →0 = →0 = = = →0 →0 1 . 1. = = =1 Jawabannya C www.belajar-matematika.com
Soal-Soal dan Pembahasan SNMPTN Matematika IPA Tahun Pelajaran 2010/2011 Tanggal Ujian: 01 Juni 2011 1. Diketahui vektor u = (a, -2, -1) dan v = (a, a, -1). Jika vektor u tegak lurus pada v , maka nilai a adalah ... A. -1 B. 0 C. 1 D. 2 E. 3 Jawab: Vektor: vektor u tegak lurus pada v maka u . v = 0 u = −2 , v = −1 −2 . −1 −1 (a – 1) (a-1) = 0 maka a = 1 −1 = a2 – 2a + 1 = 0 (a - 1)2 = 0 Jawabannya adalah C 2. Pernyataan berikut yang benar adalah ... A. Jika sin x = sin y maka x = y B. Untuk setiap vektor u , v dan w berlaku u . ( v . w ) = ( u . v ). w C. Jika b f ( x) dx = 0, maka a D. Ada fungsi f sehingga E. 1 – cos 2x = 2 cos2 x f ( x )= 0 Lim f(x) ≠ f(c) untuk suatu c xc www.belajar-matematika.com - 1 Jawab: Trigonometri, vektor, integral, limit A. Ambil nilai dimana sin x = sin y sin α = sin (1800 – α ) ambil nilai α = 600 sin 600 = sin 1200 ; tetapi 600 ≠ 1200 Pernyataan SALAH B. Operasi u . ( v . w ) tak terdefinisi karena v . w = skalar, sedangkan u = vektor vektor . skalar = tak terdefinisi Pernyataan SALAH C. Ambil contoh cari cepat hasil dimana b f ( x) dx = 0 ; a 1 Didapat b = 1 dan a = -1 maka f(x)= x x dx = 0 1 terbukti : f(x) = x bukan f(x) = 0 x2 | Pernyataan SALAH D. Ambil contoh f(x) = Lim xc f(x) = Lim x 1 ( ( = ( ( ) ( )( ) = ) ( ) Lim f(x) ≠ f(c) 2 ≠ 1 xc ) ( )( ) = ) ( ) =2 Pernyataan BENAR E. 1 – cos 2x = 1 – ( 2cos2 x – 1) = 1 + 1 - 2cos2 x = 2 - 2cos2 x = 2 ( 1 – cos2 x) Pernyataan SALAH Jawabannya adalah D www.belajar-matematika.com - 2 = (1 – 1) = 0 3. Luas daerah di bawah y = -x2 +8x dan di atas y = 6x - 24 dan terletak di kuadran I adalah.... a. ∫ (− b. ∫ (− c. ∫ (− +8 ) +8 ) +8 ) d. ∫ (6 − 24) e. ∫ (6 − 24) Jawab: Integral: +∫ ( + ∫ (− + ∫ (− + ∫ (− + ∫ (− − 2 − 24) + 2 + 24) + 2 + 24) +8 ) +8 ) kuadran I titik potong kedua persamaan : y1 = y2 -x2 +8x = 6x-24 -x2 +8x - 6x+24 = 0 -x2 +2x + 24 = 0 x2 -2x - 24 = 0 (x - 6) (x+4)0 x = 6 atau x = -4 karena di kuadran I maka yang berlaku adalah x = 6 y = 6.6 – 24= 12 berada di titik (6,12) www.belajar-matematika.com - 3 L = ∫ (− = ∫ (− +8 ) +8 ) + ∫ ((− + ∫ (− Jawabannya adalah B + 8 ) − (6 − 24)) + 2 + 24) 4. sin 350 cos 400 - cos 35 sin 400 = A. cos 50 B. sin 50 C. cos 950 D. cos 750 E. sin 750 Jawab: Trigonometri: Pakai rumus: sin (A - B) = sin A cos B - cos A Sin B A= 350 ; B = 400 = sin (350 - 400) = sin -50 Cos (90 0 - ) = sin rumus Cos (90 0 - (-50) ) = sin -50 = -50 Cos 950 = sin -50 Jawabannya adalah C 5. Diketahui g(x) = ax2 – bx + a – b habis dibagi x – 1. Jika f(x) adalah suku banyak yang bersisa a ketika dibagi x – 1 dan bersisa 3ax + b2 + 1 ketika dibagi g(x), maka nilai a adalah...... A. -1 B. -2 C. 1 D. 2 Jawab: Suku Banyak: g(x) = ax2 – bx + a – b habis dibagi x – 1 g(1) = 0 g(1) = a . 1 – b .1 + a – b = 0 =a–b+a–b=0 2a – 2b = 0 2a = 2b a = b karena a = b maka: g(x) = ax2 – ax + a – a = ax2 – ax www.belajar-matematika.com - 4 E. 3 f(x) dibagi dengan f(x-1) sisa a f(1) = a f(x) dibagi dengan g(x) sisa 3ax + b2 + 1 f(x) dibagi dengan ax2 – ax sisa 3ax + b2 + 1 f(x) dibagi dengan ax(x – 1) sisa 3ax + b2 + 1 teorema suku banyak: Jika suatu banyak f(x) dibagi oleh (x- k) akan diperoleh hasil bagi H(x) dan sisa pembagian S f(x) = (x- k) H(x) + S f(x) dibagi dengan ax(x – 1) sisa 3ax + b2 + 1 f(x) = ax (x - 1) H(x) + (3ax + b2 + 1) substitusikan nilai nol dari pembagi yaitu x = 0 dan x = 1 dari ax (x - 1) ambil x = 1 untuk x = 1 f(1) = a . 1 (1 – 1) H(0) + 3a.1 + b2 + 1 a = 0 + 3a + b2 + 1 diketahu a = b, masukkan nilai a = b a = 3a + a2 + 1 a2 + 2a + 1 = 0 (a+1)(a+1) = (a+1)2 = 0 a = -1 Jawabannya adalah A 6. Rotasi sebesar 450 terhadap titik asal diikuti dengan pencerminan terhadap y = -x memetakan titik (3,4) ke .... A. √ B. − Jawab: ,√ √ ,√ C. D. √ √ ,−√ ,−√ E. − Transformasi Geometri: cos Rotasi sebesar 450 terhadap titik asal = sin sin cos 0 1 pencerminan terhadap y = -x 1 0 www.belajar-matematika.com - 5 √ ,√
Garlic Marinated Grilled Chicken Pasta with Balsamic Reduction Glaze Submitted by Ted Lawrence Ingredients • 3 cloves garlic, minced • 4 ounces fresh basil leaves • 6 skinless, boneless chicken breast halves • 1 tablespoon salt • 1 1/2 teaspoons ground black pepper • 1 pound Whole Wheat pasta • 2 pints grape tomatoes, halved • 4oz Fresh Mozzarella • 3tbs olive oil & Some for Drizzle • 1 cup balsamic vinegar • salt and pepper to taste Directions 1. Mince garlic cloves in food processor or blender. Add 1/3 of the basil leaves to the processor, and chop until fine. Pour in 3Tbs of olive oil, and continue to process until mixture turns light yellow with flecks of basil. 2. Place the chicken breasts in a large zip-top storage bag along with 1 tablespoon salt, 1 1/2 teaspoons pepper, and rub chicken with contents from the food processer. Squeeze air out of bag and seal. Allow chicken to marinate for 2 hours, or up to overnight, turning occasionally. 3. In a small sauce pan, add 1 cup of balsamic vinegar and simmer over medium heat for about 15min or until it reduces enough to coat the back of a spoon. Cover and set aside 4. Brown chicken in a large skillet over high heat, about 4 to 5 minutes per side or until done. Allow to rest 15min tented with aluminum foil, then slice into 1/4 inch strips and set aside. 5. While chicken is cooking, bring a large pot of water to a boil over high heat. Boil the pasta until cooked through, but still firm to the bite, about 11 minutes. Drain well drizzle with olive oil, toss and place in a serving bowl. 6. Thinly slice the remaining basil leaves, cube the fresh mozzarella and tomatoes and place on top the pasta adding salt and pepper to taste. 7. Add chicken and toss together adding the reduced Balsamic sauce and serve. Serves 6, approximately 350calories per serving ...
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HARRY POtteR AND th POWeR OF NARRAtIVe By Michael Bérubé Survey after survey suggests that children in the United States are reading less often and less well. Study after study reveals that kids from seven to seventeen find literature significantly less interesting than the Internet and the Game Cube. Warning after warning is issued: unless these kids knock it off with their Grand Theft Autos and their iNanoWhatNots, something precious will pass from the earth. Now imagine that there’s one significant exception to the general decline—a mass reading phenomenon so widespread as to have become a billion-dollar industry unto itself. A veritable tulip craze of reading, in which children stay up all night reading the latest book in the series and then power up their computers the next day—not to play shoot-’em-up games, mind you, but to order the next book months in advance of its publication. How do you think serious adult readers and writers would respond to such a thing? Would they chortle in their joy? Would they be guardedly enthusiastic? Would they take the opportunity to consider why children might learn to enjoy reading in the first place, even in the midst of more technologically advanced forms of entertainment? Well, some would. But strangely, others would take it as an opportunity to complain that the books themselves aren’t good enough. Faced with a mass-cultural reading phenomenon the like of which the industrialized world has never seen, some writers and critics—taking their cue from Kafka’s hunger artist, perhaps—have looked through the books and sniffed, “Well, I suppose it’s all right that the children are reading—but really, there are much better books that they should be reading.” I refer, of course, to the Harry Potter backlash, spearheaded chiefly by Harold Bloom and A. S. Byatt. “Taking arms against Harry Potter, at this moment,” wrote a dyspeptic and beleaguered Bloom in 2000, “is to emulate Hamlet taking arms against a sea of troubles...