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Contoh surat pemberitahuan nilai mahasiswa

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Kunci Jawaban Soal Essai Paket A.pdf

Kunci jawaban Babak FINAL Jenis soal : ESSAY 1. Kinerja bensin diukur berdasarkan nilai oktan (octane number) yaitu keberadaan senyawa 2,2,4 - trimetil pentane (isooktana) dengan nilai oktan 100, sedangkan nheptana nilai oktannya adalah nol. a. Gambarkan struktur 2,2,4 – trimetil pentane dan n – heptana (20 Point) Penyelesaian : b. Gambarkan semua isomer struktur n-heptana dan namai secara IUPAC (30 Point) Penyelesaian : c. Gambarkan struktur dan nama IUPAC alkena paling sederhana yang mempunyai isomer cis dan trans. (30 Point) Penyelesaian : d. Jelaskan pengertian bensin dengan angka oktan 75 % (20 Point) Penyelesaian : Angka oktan pada bensin ditentukan dengan adanya senyawa trimetil pentane dan nheptana dimana apabila pada bensin memiliki angka oktan 100 % maka pada besin tersebut terkandung senyawa trimetil pentane banding senyawa n-heptana yaitu 100 : 0, sehingga apabila bensin dengan angka oktan 75 % maka dalam bensin tersebut terkandung 75 % senyawa trimetil pentane dan 25 % senyawa n-heptana. 2. Reaksi : 2NOBr (g)  2NO (g) + Br2 (g) H = +16,1 kJ Diketahui : Tekanan awal NOBr = 0,65 atm. : NOBr telah terurai sebanyak 28% (Saat Kstb) (a) Tuliskan bentuk tetapan kesetimbangan, Kp. (10 poin) Penyelesaian : Kp  [p NO ] 2 [p Br2 ] [p NOBr ] 2 (b) Tentukan tekanan parsial gas NOBr, NO, dan Br2 setelah tercapai keadaan kesetimbangan. (30 poin) Penyelesaian : 100  28 p NOBr   0,65 atm  0,468 atm 100 28 p NO   0,65 atm  0,182 atm 100 p Br2  28 2 100  0,65 atm  0,091 atm (c) Tentukan tekanan total sesudai tercapai kesetimbangan (20 poin) Penyelesaian : (100  28 )  (28  14 ) 114 p tot  [ ]  0,65 atm   0,65 atm  0,741 atm 100 100 (d) Hitung nilai tetapan kesetimbangan, Kp pada temperatur tersebut. (20 poin) Penyelesaian :

Kunci Jawaban dan Pembahasan MAT VII A

Kunci Jawaban dan Pembahasan PR Matematika Kelas VII 1 Bab I A. Bilangan Bulat 10. Jawaban: c Pembalap tercepat adalah pembalap yang mempunyai catatan waktu paling sedikit. Juara I pembalap B (50 menit 27 detik) Juara II pembalap E (50 menit 28 detik) Juara III pembalap F (50 menit 30 detik) Pilihan Ganda 1. Jawaban: d –6 –5 –4 –3 –2 –1 0 1 2 3 4 5 6 Dari garis bilangan tersebut diperoleh: –6 < –1 (ii) 5 > –5 (iv) Jadi, pernyataan yang benar adalah (ii) dan (iv). B. Uraian 1. Posisi hewan-hewan tersebut dapat digambar pada garis bilangan berikut. –18 ↑ Paus 2. Jawaban: a Angka yang semakin kecil menunjukkan bahwa suhu semakin dingin. Jadi, suhu yang lebih dingin dari –2°C adalah –5°C (i). a. 3. Jawaban: b Suhu di bawah nol menunjukkan suhu negatif, sedangkan suhu di atas nol menunjukkan suhu positif. Jadi, penulisan suhu kedua kota tersebut –6°C dan 20°C. 2. a. b. b. 6. Jawaban: d Posisi benda yang berada 25 cm di bawah titik 0 ditulis –25. 7. Jawaban: a Dengan menggambar dan melengkapi garis bilangan, diperoleh: –5 –4 –3 –2 –1 0 1 2 3 4 5 8. Jawaban: b Mentransfer uang berarti mengirimkan uang ke rekening seseorang. Pak Banu mentransfer uang Rp810.000,00 sehingga tabungannya berkurang Rp810.000,00. 9. Jawaban: c –6 < x ≤ –1, x bilangan bulat adalah –5, –4, –3, –2, –1. 2 Kunci Jawaban dan Pembahasan PR Matematika Kelas VII Letak bilangan 5, 3, 7, 8, 4, 6 pada garis bilangan: 4 5 –3 0 7 8 3 6 Urutannya: –6, –3, 0, 3, 6 Letak bilangan –5, 5, –10, 0, –15 pada garis bilangan: –15 –10 –5 d. 6 Urutannya: 3, 4, 5, 6, 7, 8 Letak bilangan –3, 6, 3, –6, 0 pada garis bilangan: –6 c. 12 ↑ Elang Hewan yang berada di lokasi paling dalam adalah paus. Hewan yang berada di lokasi paling tinggi adalah elang. 3 4. Jawaban: d Notasi –8 ≤ x < 1 menyatakan bahwa nilai x yang memenuhi –8, –7, –6, –5, –4, –3, –2, –1, 0. 5. Jawaban: d Diketahui –3 < x < 5, x bilangan bulat. Jadi, anggotanya meliputi –2, –1, 0, 1, 2, 3, 4. –6 0 ↑ ↑ Hiu Lumba-lumba 0 5 Urutannya: –15, –10, –5, 0, 5 Letak bilangan –36, –18, –24, –30, –12 pada garis bilangan: –36 –30 –24 –18 –12 Urutannya: –36, –30, –24, –18, –12 3. x anggota dari –5, –4, –3, –2, –1, 0, 1, 2, 3, 4, 5 a. 0 < x ≤ 3, nilai x adalah 1, 2, 3 b. –4 ≤ x ≤ 3, nilai x adalah –4, –3, –2, –1, 0, 1, 2, 3 c. x ≤ –3 atau x > 3, nilai x adalah –5, –4, –3, 4, 5 d. x < –2 dan x > –4, nilai x adalah –3 atau x = –3

kunci jawaban ipa
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KUNCI JAWABAN IPA MATEMATIKA 46. Jawaban : C y = ax² + bx + c, melalui (1, 12) 12 = a + b + c, dimana a, b, c, merupakan deret aritmetika y’ = 2ax + b m = 2 . a. 1 + 4 6 = 2a + 4 a =1 a + c = 2b c=7 3a + 2b + c = 3 + 8 +7 = 18 47. Jawaban : C Misal cos x = y = 81 2x – 3y = - 81 51. Jawaban : B tan p = √3 ---- p = 60° sin q = ---- cos q = √ √ = cos (p + q) + cos 2q = cos 60° cos q – sin 60° sin q + cos² q - sin² q = √ - √ + 52. Jawaban : B f(x) = , g(x) = 7log (f o g)(x) = 7log /(1 - 27log ) + cos +cos (sin ) + (sin (f o g)(x) + (f o g)( ) = = A (x 2 sin ) – sin ) + (sin – sin )= ( ) = ( ) ( ) + = -1 A . 2 sin sin 53. Jawaban : A = A . 2 sin sin (π - ) = A . 2 sin sin = A . 2 sin 1 = 2A A=½ 48. Jawaban : D ² - ² ² =1 Asimtot : y = x, sejajar 6x – 3y + 5 = 0 =2 =4 ² = 16 1 −1 2 0 1 =( )( )= 2 1 3 1 2 −1 1 −2 ( ) 3 +2 +1 = k + 1 + 6p + 4 = -2 7k = -7 --- k = -1 1 −2 =( ) −1 0 0 −1 0 2 (( )-1 = ( ) = (− − ) 1 1 a + b + c + d = -2 54. Jawaban : D I I=I I √36 + 4 + 25 = √ ² + 36 + 4 x² = 25 x = 5 atau x = -5 a .p <0 49. Jawaban : D Sudah jelas 50. Jawaban : B 81 x 81 x log = log ----- log = log IaIIpI 6 12 10 √65 .√65 = log² = log 81 log x y log = log ........1) ---- x log = ylog 81 = log² Agar -6x – 12 + 10 < 0, maka nilai x yang memenuhi hanyalah x = 5 55. Jawaban : B (K’L’) = = log 81 log (1) : (2) ----- ........2) ² ² = log = log ---- x = y Dari (1) diperoleh log . log = log 81 . log log = log 81 <0 1 3 2 √2 ² + (3 √2)² = √26

Risk Factors involved in High Risk Pregnancy

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Treatment of Infertility
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Our Fertility clinic / Test Tube Baby Centre, is the best IVF clinic in Surat Gujarat, offers excellent IVF success rates with affordable IVF cost with team of top Infertility Specialists & Fertility Doctors in Surat,India.The fertility specialist at Blossom are committed to offer to the patients clinical excellence, cost-effective treatment options, personalized compassionate care, and exceptional success rate. Contact The Blossom Fertility and IVF Centre today for Best infertility treatments like IVF, ICSI, IUI, IMSI, Surrogacy in Surat at http://www.blossomivfindia.com or +91 261 2470333 or info@blossomivfindia.com and gather all information to attain happy parenthood.

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IVF in Surat
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Our Fertility clinic / Test Tube Baby Centre, is the best IVF clinic in Surat Gujarat, offers excellent IVF success rates with affordable IVF cost with team of top Infertility Specialists & Fertility Doctors in Surat,India.The fertility specialist at Blossom are committed to offer to the patients clinical excellence, cost-effective treatment options, personalized compassionate care, and exceptional success rate. Contact The Blossom Fertility and IVF Centre today for Best infertility treatments like IVF, ICSI, IUI, IMSI, Surrogacy in Surat at http://www.blossomivfindia.com or +91 261 2470333 or info@blossomivfindia.com and gather all information to attain happy parenthood.

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