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CONTOH DIAGRAM BATANG DALAM EKONOMI indonesia

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Electrolux Major Appliances 30-INCH SLIDE-IN ELECTRIC RANGE ...

Product No. EW30ES6CGS6 37663376J76S6 Series 30" elec Color stainless Market Canada Wiring Diagram 318550155 Owner's Guide 318203847 Installation Instructions 318201615 Service Data Sheet 318127078 Quick Start Guide 318203404 30-INCH SLIDE-IN RANGE EW30ES65GS.bmp CEW30ES65GWB.eps BEW30ES6CGS5.eps TEW30ES65GSE.eps ELECTRIC DEW30DS6CGS6.eps 318550155-1.eps 318550155-2.eps Model No. EW30ES6CG Electrolux Major Appliances P.O. BOX 8020 CHARLOTTE, NC 28262 Publication No. 5995581237 10/11/22 (EN/SERVICE/ECL) 377 Publication No: 5995581237 EW30ES6CGS6 BACKGUARD 11/10 2 EW30ES6CGS6 Publication No: 5995581237 BACKGUARD POS. NO 18 19 # 20 # 21 22 23 24 25 97A# 99 # 99*# PART NO. 318900301 318387121 316576612 316524400 318905005 5304417153 5303307980 5303131801 316576432 316535201 318578306 DESCRIPTION Subframe, control Control Assembly, glass, black, w/interface Controller, electronic, ES630 Screw, control mtg, 6-32 x .25, (5) Panel, service, stainless Screw, shoulder, 8-18 X 1/2, (4) Screw, 8-32 x 0.437, (8) Screw, 10 x 3/8 Board, power, UIB Board, power supply, 8V Harness, wiring, power supply * # * # * * 318578320 318578321 318163602 5303211311 Harness, wiring, controller, to UIB Harness, wiring, UIB, to power boards Cleaner, stainless steel Screw, 8-18 x 0.500 # Functional Parts * Non-Illustrated Parts 3 11/10 Publication No: 5995581237 EW30ES6CGS6 BODY 11/10 4 EW30ES6CGS6 Publication No: 5995581237 BODY POS. NO 1 1A 2 3 4 4A 6 6A 6B 7 8 8A 8B 8B* 9 10 11 12 13 13* 14 # * # 15 18 20 21 24 29 37 # 39 # 53 # 54 # 54* 54* 54* 55 58A 58B 58C 58D 59 59* 62 62* 66 # 67 # 70 71 76 77 77A # Functional Parts * Non-Illustrated Parts

Westhill Consulting Employment Blog: Jakarta Indonesia’s Oil and Gas Industry Will Need to Fill At L

Jakarta Indonesia's oil and gas industry is in need to load at least 8,000 jobs by 2015. From present up to 2015, the country’s oil and gas industry is threatened of losing almost three per cent of its employees in general, because of steadily low natural gas prices. There are two primary factors, growth in certain operations and age-related attrition across the industry, yet on the other hand, will offset more job losses and in fact contribute to increased overall hiring needs. Alterations in the figure of jobs will not be the same across all industry sectors. For instance, the oil and gas services sector, even though shaken by commodity price instability, will still need to fill about 4,700 jobs between 2012 and 2015.

GP2D120 Data Sheet.fm - Sharp Microelectronics of the Americas

GP2D120 Optoelectronic Device FEATURES • Analog output • Effective range: 4 to 30 cm • Typical response time: 39 ms 1 2 3 • Typical start up delay: 44 ms • Average Current Consumption: 33 mA DESCRIPTION PIN SIGNAL NAME The GP2D120 is a distance measuring sensor with integrated signal processing and analog voltage output. 1 VO 2 GND 3 VCC GP2D120-8 Figure 1. Pinout GND VCC PSD SIGNAL PROCESSING CIRCUIT VOLTAGE REGULATOR OSCILLATOR CIRCUIT OUTPUT CIRCUIT LED DRIVE CIRCUIT Vo LED MEASURING DISTANCE IC GP2D120-4 Figure 2. Block Diagram 1 Data Sheet GP2D120 ELECTRICAL SPECIFICATIONS Absolute Maximum Ratings Ta = 25°C, VCC = 5 VDC PARAMETER SYMBOL RATING UNIT Supply Voltage VCC -0.3 to +7 V Output Terminal Voltage VO -0.3 to (VCC +0.3) V Operating Temperature Topr -10 to +60 °C Storage Temperature Tstg -40 to +70 °C Operating Supply Voltage PARAMETER SYMBOL RATING UNIT Operating Supply Voltage VCC 4.5 to 5.5 V Electro-optical Characteristics Ta = 25°C, VCC = 5 VDC PARAMETER SYMBOL Measuring Distance Range ΔL Output Terminal Voltage VO CONDITIONS MIN. TYP. MAX. UNIT NOTES 4 — 30 cm 1, 2 L = 30 cm...

PEMBAHASAN DAN KUNCI JAWABAN GEOGRAFI KELAS XII ...

PEMBAHASAN DAN KUNCI JAWABAN GEOGRAFI KELAS XII PAKET B 1. Berdasarkan soal nomor 1 a. Konsep aglomerasi adalah merupakan gabungan, kumpulan, 2 atau lebih pusat kegiatan dalam 1 lokasi/kawasan terterntu seperti kawasan industri, pemukiman, perdagangan, dsb. b. Konsep morfologi menjelaskan kenampakan bentuk-bentuk muka bumi, seperti dataran rendah, lereng, bukit/dataran tinggi. c. Konsep pola menitik beratkan pada pola keruangan baik fisik maupun sosialnya seperti pola permukiman penduduk, pola aliran sungai, dsb. d. Konsep lokasi mengkaji letak suatu objek dipermukaan bumi. Pada konsep ini utamanya dalam menjawab pertanyaan dimana (where). e. Konsep ketergantungan adalah konsep yang menunjukkan keterkaitan keruangan antar wilayah akibat adanya perbedaan potensi antar wilayah. Seperti keterkaitan antara desa dengan kota. Kunci jawaban D 2. Prinsip-prinsip geografi ada 4 a. Prinsip deskripsi, merupakan penjelasan lebih jauh mengenai gejala-gejala yang diselidiki/dipelajari. Deskripsi disajikan dalam bentuk tulisan, diagram tabel/gambar/peta. b. Prinsip korologi, merupakan gejala, fakta/masalah geografi disuatu tempat yang ditinjau dari sebaran, interelasi, interaksi, dan integrasinya dalam ruang. c. Prinsip persebaran, merupakan suatu gejala dan fakta yang tersebar tidak merata dipermukaan bumi. d. Prinsip interelasi, merupakan suatu hubungan yang saling terkait dalam ruang antara gejala yang 1 dengan gejala lain. e. Prinsip distribusi, merupakan suatu gejala dan fakta yang tidak merata dipermukaan bumi.

Kunci Jawaban Soal Essai Paket A.pdf

Kunci jawaban Babak FINAL Jenis soal : ESSAY 1. Kinerja bensin diukur berdasarkan nilai oktan (octane number) yaitu keberadaan senyawa 2,2,4 - trimetil pentane (isooktana) dengan nilai oktan 100, sedangkan nheptana nilai oktannya adalah nol. a. Gambarkan struktur 2,2,4 – trimetil pentane dan n – heptana (20 Point) Penyelesaian : b. Gambarkan semua isomer struktur n-heptana dan namai secara IUPAC (30 Point) Penyelesaian : c. Gambarkan struktur dan nama IUPAC alkena paling sederhana yang mempunyai isomer cis dan trans. (30 Point) Penyelesaian : d. Jelaskan pengertian bensin dengan angka oktan 75 % (20 Point) Penyelesaian : Angka oktan pada bensin ditentukan dengan adanya senyawa trimetil pentane dan nheptana dimana apabila pada bensin memiliki angka oktan 100 % maka pada besin tersebut terkandung senyawa trimetil pentane banding senyawa n-heptana yaitu 100 : 0, sehingga apabila bensin dengan angka oktan 75 % maka dalam bensin tersebut terkandung 75 % senyawa trimetil pentane dan 25 % senyawa n-heptana. 2. Reaksi : 2NOBr (g)  2NO (g) + Br2 (g) H = +16,1 kJ Diketahui : Tekanan awal NOBr = 0,65 atm. : NOBr telah terurai sebanyak 28% (Saat Kstb) (a) Tuliskan bentuk tetapan kesetimbangan, Kp. (10 poin) Penyelesaian : Kp  [p NO ] 2 [p Br2 ] [p NOBr ] 2 (b) Tentukan tekanan parsial gas NOBr, NO, dan Br2 setelah tercapai keadaan kesetimbangan. (30 poin) Penyelesaian : 100  28 p NOBr   0,65 atm  0,468 atm 100 28 p NO   0,65 atm  0,182 atm 100 p Br2  28 2 100  0,65 atm  0,091 atm (c) Tentukan tekanan total sesudai tercapai kesetimbangan (20 poin) Penyelesaian : (100  28 )  (28  14 ) 114 p tot  [ ]  0,65 atm   0,65 atm  0,741 atm 100 100 (d) Hitung nilai tetapan kesetimbangan, Kp pada temperatur tersebut. (20 poin) Penyelesaian :

Kunci Jawaban dan Pembahasan MAT VII A

Kunci Jawaban dan Pembahasan PR Matematika Kelas VII 1 Bab I A. Bilangan Bulat 10. Jawaban: c Pembalap tercepat adalah pembalap yang mempunyai catatan waktu paling sedikit. Juara I pembalap B (50 menit 27 detik) Juara II pembalap E (50 menit 28 detik) Juara III pembalap F (50 menit 30 detik) Pilihan Ganda 1. Jawaban: d –6 –5 –4 –3 –2 –1 0 1 2 3 4 5 6 Dari garis bilangan tersebut diperoleh: –6 < –1 (ii) 5 > –5 (iv) Jadi, pernyataan yang benar adalah (ii) dan (iv). B. Uraian 1. Posisi hewan-hewan tersebut dapat digambar pada garis bilangan berikut. –18 ↑ Paus 2. Jawaban: a Angka yang semakin kecil menunjukkan bahwa suhu semakin dingin. Jadi, suhu yang lebih dingin dari –2°C adalah –5°C (i). a. 3. Jawaban: b Suhu di bawah nol menunjukkan suhu negatif, sedangkan suhu di atas nol menunjukkan suhu positif. Jadi, penulisan suhu kedua kota tersebut –6°C dan 20°C. 2. a. b. b. 6. Jawaban: d Posisi benda yang berada 25 cm di bawah titik 0 ditulis –25. 7. Jawaban: a Dengan menggambar dan melengkapi garis bilangan, diperoleh: –5 –4 –3 –2 –1 0 1 2 3 4 5 8. Jawaban: b Mentransfer uang berarti mengirimkan uang ke rekening seseorang. Pak Banu mentransfer uang Rp810.000,00 sehingga tabungannya berkurang Rp810.000,00. 9. Jawaban: c –6 < x ≤ –1, x bilangan bulat adalah –5, –4, –3, –2, –1. 2 Kunci Jawaban dan Pembahasan PR Matematika Kelas VII Letak bilangan 5, 3, 7, 8, 4, 6 pada garis bilangan: 4 5 –3 0 7 8 3 6 Urutannya: –6, –3, 0, 3, 6 Letak bilangan –5, 5, –10, 0, –15 pada garis bilangan: –15 –10 –5 d. 6 Urutannya: 3, 4, 5, 6, 7, 8 Letak bilangan –3, 6, 3, –6, 0 pada garis bilangan: –6 c. 12 ↑ Elang Hewan yang berada di lokasi paling dalam adalah paus. Hewan yang berada di lokasi paling tinggi adalah elang. 3 4. Jawaban: d Notasi –8 ≤ x < 1 menyatakan bahwa nilai x yang memenuhi –8, –7, –6, –5, –4, –3, –2, –1, 0. 5. Jawaban: d Diketahui –3 < x < 5, x bilangan bulat. Jadi, anggotanya meliputi –2, –1, 0, 1, 2, 3, 4. –6 0 ↑ ↑ Hiu Lumba-lumba 0 5 Urutannya: –15, –10, –5, 0, 5 Letak bilangan –36, –18, –24, –30, –12 pada garis bilangan: –36 –30 –24 –18 –12 Urutannya: –36, –30, –24, –18, –12 3. x anggota dari –5, –4, –3, –2, –1, 0, 1, 2, 3, 4, 5 a. 0 < x ≤ 3, nilai x adalah 1, 2, 3 b. –4 ≤ x ≤ 3, nilai x adalah –4, –3, –2, –1, 0, 1, 2, 3 c. x ≤ –3 atau x > 3, nilai x adalah –5, –4, –3, 4, 5 d. x < –2 dan x > –4, nilai x adalah –3 atau x = –3

Design of All Digital FM Receiver Circuit - OpenCores

1. Introduction The design of the All Digital FM Receiver circuit in this project uses Phase Locked Loop (PLL) as the main core. The task of the PLL is to maintain coherence between the input (modulated) signal frequency, ωi and the respective output frequency, ωo via phase comparison. This self-correcting ability of the system also allows the PLL to track the frequency changes of the input signal once it is locked. Frequency modulated input signal is assumed as a series of numerical values (digital signal) via 8-bit of analog to digital conversion (ADC) circuit. The FM Receiver gets the 8 bit signal every clock cycle and outputs the demodulated signal. The All Digital FM Receiver circuit is designed using VHDL, then simulated and synthesized using ModelSim SE 6 simulator and Xilinx ISE 6.3i, respectively. FPGA implementation also provided, here we use Virtex2 device. The real measurement is done using ChipScope Pro 6.3i. 2. Architecture Description The system of All Digital FM Receiver consists of a digital PLL cascaded with digital low pass filter. The block diagram of system is shown in Fig. 1.

LM3089 FM Receiver IF System
by dietdude 0 Comments favorite 5 Viewed Download 0 Times

LM3089 FM Receiver IF System Y General Description The LM3089 has been designed to provide all the major functions required for modern FM IF designs of automotive high-fidelity and communications receivers Y Features Y Y Y Three stage IF amplifier limiter provides 12 mV (typ) b 3 dB limiting sensitivity Balanced product detector and audio amplifier provide 400 mV (typ) of recovered audio with distortion as low as 0 1% with proper external coil designs Y Y Four internal carrier level detectors provide delayed AGC signal to tuner IF level meter drive current and interchannel mute control AFC amplifier provides AFC current for tuner and or center tuning meters Improved operating and temperature performance especially when using high Q quadrature coils in narrow band FM communications receivers No mute circuit latchup problems A direct replacement for CA3089E Connection Diagram Dual-In-Line Package TL H 7149 – 2 Top View Order Number LM3089N See NS Package Number N16E C1995 National Semiconductor Corporation TL H 7149 RRD-B30M115 Printed in U S A LM3089 FM Receiver IF System September 1992 Toko America 1250 Feehanville Drive Mount Prospect IL 60056 (312) 297-0070 TL H 7149 – 1

LM3089 FM Receiver IF System (Rev. A) - Texas Instruments

LM3089 FM Receiver IF System Literature Number: SNOSBQ6A LM3089 FM Receiver IF System The LM3089 has been designed to provide all the major functions required for modern FM IF designs of automotive high-fidelity and communications receivers Y Features Y Y Y Three stage IF amplifier limiter provides 12 mV (typ) b 3 dB limiting sensitivity Balanced product detector and audio amplifier provide 400 mV (typ) of recovered audio with distortion as low as 0 1% with proper external coil designs Y Y Four internal carrier level detectors provide delayed AGC signal to tuner IF level meter drive current and interchannel mute control AFC amplifier provides AFC current for tuner and or center tuning meters Improved operating and temperature performance especially when using high Q quadrature coils in narrow band FM communications receivers No mute circuit latchup problems A direct replacement for CA3089E Connection Diagram bs ol et Dual-In-Line Package e Y General Description TL H 7149 – 2 Top View O Order Number LM3089N See NS Package Number N16E C1995 National Semiconductor Corporation TL H 7149 RRD-B30M115 Printed in U S A LM3089 FM Receiver IF System

Must sees in Jakarta, Indonesia
by sharp439 0 Comments favorite 11 Viewed Download 0 Times

The central tourist attractions are located in the center of the city. Westhill Consulting Travel & Tours Singapore provides you with useful information of must sees in Jakarta, Indonesia Kota district is the centre of old Batavia. It is the tourist hub of Jakarta. The focal action is centered in the historic Taman Fatahillah, a paved square that looks like it came from another era. If you visit the old port area, Sunda Kelapa, you can see the schooners returning from the high seas to trade their exotic spices. It is a picture immortalized in Joseph Conrad evocative descriptions. Jakarta’s most unforeseen attractions is the vibrantly painted sailing ships are.

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